Computer Science Illuminated
6th Edition
ISBN: 9781284055917
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Chapter 2, Problem 34E
Program Plan Intro
a.
Decimal number:
- A decimal number is a number in which the whole number part and the fractional part is separated by a decimal point.
- The dot is known as a decimal point of a decimal number.
- Hence decimal numbering system is a method for representing both integer and non-integer numbers.
Hexadecimal number:
- Hexadecimal number system is a positional number system with a radix or base of 16.
- These are widely used by computer
system designers and programmers. - Each hexadecimal digit represents four binary digits which is also known as nibble.
- Hexadecimal numbers are 0-9 and letters A-F.
Explanation of Solution
b.
Conversion of decimal number 1939 into hexadecimal value:
- Divide 1939 by 16 and it returns 121 as quotient and 3 as remainder.
- Divide 121 by 16 and it returns 7 as quotient and 9 as remainder.
- Divide 7 by 16 and it is not possible as 7 is less than 16...
Explanation of Solution
c.
Conversion of decimal number 1 into hexadecimal value:
- Divide number 1 by 16. It is not possible as 1 is less than 16...
Explanation of Solution
d.
Conversion of decimal number 998 into hexadecimal value:
- Divide 998 by 16 and it returns 62 as quotient and 6 as remainder.
- Divide 62 by 16 and it returns 3 as quotient and 14 as remainder. The corresponding hexadecimal value for 14 is E...
Explanation of Solution
e.
Conversion of decimal number 43 into hexadecimal value:
- Divide 43 by 16 and it returns 2 as quotient and 11 as remainder. The corresponding hexadecimal value for 11 is B.
- Divide 2 by 16 and it is not possible as 2 is less than 16...
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Methods (Ch6) - Review
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public static double myRoot(int number) {
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return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
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Chapter 2 Solutions
Computer Science Illuminated
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 1TQCh. 2 - Prob. 2TQCh. 2 - Prob. 3TQCh. 2 - Prob. 4TQ
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