You go to a convenience store to buy candy and find the owner to be rather odd. He allows you to buy pieces only in multiples of tour, and to buy four, you need $0.23. He allows you only to use 3 pennies and 2 dimes. You have a bunch of pennies and dimes, and instead of counting them, you decide to weigh them. You have 636.3 g of pennies, and each penny weighs an average of 3.03 g. Each dime weighs an average of 2.29 g. Each piece of candy weighs an average of 10.23 g. How many pennies do you have? How many dimes do you need to buy as much candy as possible? How much would all of your dimes weigh? How many pieces of candy could you buy (based on the number of dimes from part b)? How much would this candy weigh? How many pieces of candy could you buy with twice as many dimes?
You go to a convenience store to buy candy and find the owner to be rather odd. He allows you to buy pieces only in multiples of tour, and to buy four, you need $0.23. He allows you only to use 3 pennies and 2 dimes. You have a bunch of pennies and dimes, and instead of counting them, you decide to weigh them. You have 636.3 g of pennies, and each penny weighs an average of 3.03 g. Each dime weighs an average of 2.29 g. Each piece of candy weighs an average of 10.23 g. How many pennies do you have? How many dimes do you need to buy as much candy as possible? How much would all of your dimes weigh? How many pieces of candy could you buy (based on the number of dimes from part b)? How much would this candy weigh? How many pieces of candy could you buy with twice as many dimes?
You go to a convenience store to buy candy and find the owner to be rather odd. He allows you to buy pieces only in multiples of tour, and to buy four, you need $0.23. He allows you only to use 3 pennies and 2 dimes. You have a bunch of pennies and dimes, and instead of counting them, you decide to weigh them. You have 636.3 g of pennies, and each penny weighs an average of 3.03 g. Each dime weighs an average of 2.29 g. Each piece of candy weighs an average of 10.23 g.
How many pennies do you have?
How many dimes do you need to buy as much candy as possible?
How much would all of your dimes weigh?
How many pieces of candy could you buy (based on the number of dimes from part b)?
How much would this candy weigh?
How many pieces of candy could you buy with twice as many dimes?
Expert Solution
Interpretation Introduction
(a)
Interpretation:
Number of pennies on hand should to be calculated ·
Concept Introduction:
An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.
Answer to Problem 2ALQ
There are 210 pennies on hand.
Explanation of Solution
Total weight of the pennies are product of single unit of pennies ·
Following equation can be applied for solving problem ·
x1=t1d1
Where,
x1 represents number of pennies on the hand ·
t1 represents total weight of pennies on hand ·
d1 represents the average weight of a penny ·
Total weight of pennies on the hand is equals to 636·3g
Average weight of a penny is equals to 3·03g
Substitute 636·3g for number of pennies and 3·03 for average weight of penny
x1=t1d1x1=636·3g3·03gx1=210
There are 210 pennies on the hand·
Expert Solution
Interpretation Introduction
(b)
Interpretation:
Number of dimes need to buy candies as much as possible should be calculated.
Concept Introduction:
An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.
Answer to Problem 2ALQ
There should be 140 dimes to buy candies as much as possible.
Explanation of Solution
Seller is accepting only 3 pennies and 2 dimes. There are 210 pennies on the hand, therefore dimes can be used to buy can be calculated according to following equation.
y1=x13×2
Where ,
y1 represents number of dimes should be needed to buy candies ·
x1 represents number of pennies on the hand·
Substitute 210 for number of pennies on the hand·
y1=x13×2y1=2103×22y1=140
There should be 140 dimes to buy candies as much as possible.
Expert Solution
Interpretation Introduction
(c)
Interpretation:
Weight of all dimes should be calculated.
Concept Introduction:
An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.
Answer to Problem 2ALQ
Total weight of the dimes is equal to 320.6g.
Explanation of Solution
Total weight of dimes equals to number of dimes into average weight of a dime ·
Following equation can be used for the calculation.
n1=y1×d1
Where,
n1 represents total weight of dimes
y1 represents total number of dimes
d1 represents average weight of a dime
Substitute total number of dimes is 140 and average weight of dime is 2.29g
n1=x1×d1n1=140×2.29gn1=320.6g
Total weight of dimes is equals to 320.6g.
Expert Solution
Interpretation Introduction
(d)
Interpretation:
Amount of candies that can be bought should be calculated.
Concept Introduction:
An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.
Answer to Problem 2ALQ
Number of candies that can be bought is 240 ·
Explanation of Solution
Total sum of pennies and total sum of dimes is the total money which can be spent for candies. Following equation can be used to determine total amount of candies.
w1=[x1×b1]+(y1×a1)k1×4
Where,
w1 represents sum of total candies
x1 represents the number of pennies
b1 represents the value of a penny
y1 represents the number of dimes
a1 represents the value of a dime
k1 represents value of four candies
Substitute value of a dime is equals to 0·10$ and value of a penny equals to 0·01$ · number of pennies are 210 and number of dimes are 140 · Value of four candies is 0·23$
An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.
Answer to Problem 2ALQ
Total weight of the candies is equals to 2864·4g ·
Explanation of Solution
Total weight is the total sum of all candies bought·
Following equation can be used for calculation of total weight.
W2=W1×C1
Where,
W2 represents weight of candies,
W1 represents the number of candies
C1 represents average weight of candies
Substitute number of candies is 280 and average weight of candies is 10.23
W2=W1×C1W2=280×10.23gW2=2864·4g
Weight of candies is 2864·4g.
Expert Solution
Interpretation Introduction
(e)
Interpretation:
Number of candies can be bought with twice of dimes should be calculated.
Concept Introduction:
An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.
Answer to Problem 2ALQ
Number of candies can be bought with twice of dimes is 280.
Explanation of Solution
Even though dimes twice of dime ( 280 dimes)is on hand, number of pennies are limited· seller is accepting 3 pennies with 2 dimes. Hence, number of candies can be bought is equivalent to amount can be bought with 140 dimes·
Number of candies can be bought is 280 ·.
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Draw the product of the reaction shown below. Ignore inorganic
byproducts.
+
O
SnCl2
Drawing
Q4. Label the reaction most likely to take place (E1, SN1, E2, SN2 or a combination of these) under
the following conditions. Draw the major product(s), include stereochemistry when relevant.
a)
b)
tBuOK
acetone
CN
CH3OH
Show work with explanation needed. Don't give Ai generated solution
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell