Concept explainers
(a)
Interpretation:
The systematic name for the formula
Concept introduction:
Polyatomic ions are those in which atoms of more than one elements are present. Generally, the majority of the polyatomic ions are oxoanions in which a non-metal is bonded to one or more oxygen atoms.
The general rules for naming a family of two oxoanions are:
1) The ion with more oxygen atoms takes the non-metal root and the suffix
2) The ion with fewer oxygen atoms takes the non-metal root and the suffix
(b)
Interpretation:
The systematic formula for potassium dichromate is to be determined.
Concept introduction:
The general rules for naming oxoanion compounds are:
1) The ion with the most number of oxygen atoms has the
2) The one with one less oxygen atom does not have the
3) The ion with two fewer oxygen atoms has just the root and the suffix
4) The ion with three fewer oxygen atoms has the prefix
(c)
Interpretation:
The systematic name for
Concept introduction:
Polyatomic ions are those in which atoms of more than one elements are present. Generally, the majority of the polyatomic ions are oxoanions in which a non-metal is bonded to one or more oxygen atoms.
The general rules for naming a family of two oxoanions are:
1) The ion with more oxygen atoms takes the non-metal root and the suffix
2) The ion with fewer oxygen atoms takes the non-metal root and the suffix
(d)
Interpretation:
The systematic formula for potassium carbonate dihydrate is to be determined.
Concept introduction:
The general rules for naming ionic compounds are:
1) The names and formulas give the positive ion first and the negative ion second for all ionic compounds.
2)For binary ionic compounds, the cation name is the same as that of the metal whereas the anion name has the suffix
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Chapter 2 Solutions
CHEMISTRY: THE MOLECULAR NATURE OF MATTE
- Using line angle formulas, draw thestructures of and name four alkanes that have total of 7carbons, one of which is tertiary.Please explain this in detail and can you also explain how to approach a similar problem like this as well?arrow_forwardUsing dashed line wedge projections drawthe indicated compounds and indicate whether thecompound you have drawn is R or S.(a) The two enantiomers of 2-chlorobutane. Can you please explain your steps and how you would approach a similar problem. Thank you!arrow_forward5) There are no lone pairs shown in the structure below. Please add in all lone pairs and then give the hybridization scheme for the compound. (8) 10,11 7) 1.2.3 H 4 | 14 8) COC 12 13 H 16 15 H7 9) - 5.6 C 8 H 10) H 1). 2) 3)_ 11) 12) 13) 4)_ 14) 5) 15) 16) 6)arrow_forward
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- Hello! I have a 500 Hz H-NMR for 1,5-bis-(4-methoxyphenyl)-penta-1,4-dien-3-one. I need to label the signals with the corresponding H's. Then, find out if the two alkenes are cis or trans by calculating the J values. I believe that I have the H-NMR labeled correctly, but not sure if I got the J values correct to determine if the two alkenes in the compound will make the compound cis or trans.arrow_forwardWhat is the only possible H-Sb-H bond angle in SbH3?arrow_forwardpls helparrow_forward
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