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Math EP FUND.OF DIFF.EQUATIONS-MYLAB (18 WK)

The differential equation d y d x = x − y − 1 x + y + 5 . The solution of the differential equation d y d x = x − y − 1 x + y + 5 is x + 5 y + x y + 1 2 ( y 2 − x 2 ) = C _ . The differential equation is, d y d x = x − y − 1 x + y + 5 Separate the variables and rewrite the differential equation as follows. ( x + y + 5 ) d y = ( x − y − 1 ) d x x d y + y d y + 5 d y = x d x − y d x − d x ( x d y + y d x ) + y d y + 5 d y = x d x − d x d ( x y ) + ( y + 5 ) d y = ( x − 1 ) d x Integrate both sides of the equation. ∫ d ( x y ) + ∫ ( y + 5 ) d y = ∫ ( x − 1 ) d x x y + y 2 2 + 5 y = x 2 2 − x + C x y + y 2 2 + 5 y − x 2 2 + x = C x + 5 y + x y + 1 2 ( y 2 − x 2 ) = C Thus, the solution of the differential equation d y d x = x − y − 1 x + y + 5 is x + 5 y + x y + 1 2 ( y 2 − x 2 ) = C _ .

The differential equation d y d x = x − y − 1 x + y + 5 . The solution of the differential equation d y d x = x − y − 1 x + y + 5 is x + 5 y + x y + 1 2 ( y 2 − x 2 ) = C _ . The differential equation is, d y d x = x − y − 1 x + y + 5 Separate the variables and rewrite the differential equation as follows. ( x + y + 5 ) d y = ( x − y − 1 ) d x x d y + y d y + 5 d y = x d x − y d x − d x ( x d y + y d x ) + y d y + 5 d y = x d x − d x d ( x y ) + ( y + 5 ) d y = ( x − 1 ) d x Integrate both sides of the equation. ∫ d ( x y ) + ∫ ( y + 5 ) d y = ∫ ( x − 1 ) d x x y + y 2 2 + 5 y = x 2 2 − x + C x y + y 2 2 + 5 y − x 2 2 + x = C x + 5 y + x y + 1 2 ( y 2 − x 2 ) = C Thus, the solution of the differential equation d y d x = x − y − 1 x + y + 5 is x + 5 y + x y + 1 2 ( y 2 − x 2 ) = C _ .

Solution Summary: The author explains how to solve the differential equation dy

EP FUND.OF DIFF.EQUATIONS-MYLAB (18 WK)

EP FUND.OF DIFF.EQUATIONS-MYLAB (18 WK)

9th Edition

ISBN: 9780135963777

Author: Nagle

Publisher: PEARSON CO

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EP FUND.OF DIFF.EQUATIONS-MYLAB (18 WK)

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