Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 2, Problem 27P
The following table shows the results of different matings between jimsonweed plants that had either purple or white flowers and spiny or smooth pods. Determine the dominant allele for the two traits and indicate the genotypes of the parents for each of the crosses.
| Parents | Offspring | |||
| Purple Spiny | White Spiny | Purple Smooth | White Smooth | |
| a. purple spiny X purple spiny | 94 | 32 | 28 | 11 |
| b. purple spiny X purple smooth | 40 | 0 | 38 | 0 |
| c. purple spiny X white spiny | 34 | 30 | 0 | 0 |
| d. purple spiny X white spiny | 89 | 92 | 31 | 27 |
| e. purple smooth X purple smooth | 0 | 0 | 36 | 11 |
| f. white spiny X white spiny | 0 | 45 | 0 | 16 |
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Using the following information perform following crosses using the forked line and predict all possible phenotypes types of the offspring. List the number and description of the phenotypes of the offspring. 1. aa BB Cc Dd Ee X aa bb Cc Dd EE 2. Ff Rr Gg dd Bb X Ff RR Gg Dd Bb 3. Dd gg JJ bb Hh Ee X DD GG Jj Bb Hh Ee
a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1
Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5
The height of the parent plant 2
Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm.
c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5
Gametes – D1D2D3d4d5 × d1d2d3D4D5
F1 generation – D1d1D2d2D3d3D4d4D5d5
The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm
Hence,
Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5
Phenotype of…
Use the figure and the following description to answer the question(s) below.
In a particular plant, leaf color is controlled by gene locus D. Plants with at least one allele D have dark green leaves, and plants with the
homozygous recessive dd genotype have light green leaves. A true- breeding, dark- leaved plant is crossed with a light- leaved one, and the
F1 offspring is allowed to self- pollinate. The predicted outcome of the F2 is diagrammed in the Punnett square shown in the figure, where 1,2,3,
and 4 represent the genotypes corresponding to each box within the square.
D
d
D
1
2
4
Which of the boxes marked 1- 4 correspond to plants with a heterozygous genotype?
2 and 3
1
1,2, and 3
2, 3, and 4
3.
Chapter 2 Solutions
Genetics: From Genes to Genomes
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Ch. 2 - Some inbred strains of the weedy plant Arabidopsis...Ch. 2 - Among Native Americans, two types of earwax...Ch. 2 - Imagine you have just purchased a black stallion...Ch. 2 - If you roll a die singular of dice, what is the...Ch. 2 - In a standard deck of playing cards, four suits...Ch. 2 - How many genetically different eggs could be...Ch. 2 - What is the probability of producing a child that...Ch. 2 - A mouse sperm of genotype a B C D E fertilizes an...Ch. 2 - Your friend is pregnant with triplets. She thinks...Ch. 2 - Galactosemia is a recessive human disease that is...Ch. 2 - Albinism is a condition in which pigmentation is...Ch. 2 - A cross between two pea plants, both of which grew...Ch. 2 - A third-grader decided to breed guinea pigs for...Ch. 2 - The self-fertilization of an pea plant produced...Ch. 2 - The achoo syndrome sneezing in response to bright...Ch. 2 - A pea plant from a pure-breeding strain that is...Ch. 2 - The following table shows the results of different...Ch. 2 - A pea plant heterozygous for plant height, pod...Ch. 2 - In the fruit fly Drosophila melanogaster, the...Ch. 2 - Based on the information you discovered in the...Ch. 2 - Considering the yellow and green pea color...Ch. 2 - What would have been the outcome the genotypic and...Ch. 2 - Recall that Mendel obtained pure-breeding with...Ch. 2 - The gene that likely controlled flower color...Ch. 2 - For each of the following human pedigrees,...Ch. 2 - Consider the pedigree that follows for cutis laxa,...Ch. 2 - A young couple went to see a genetic counselor...Ch. 2 - Huntington disease is a rare fatal, degenerative...Ch. 2 - Is the disease shown in the following pedigree...Ch. 2 - Figure 2.22 shows the inheritance of Huntington...Ch. 2 - Consider the cystic fibrosis pedigree in Figure...Ch. 2 - Prob. 42PCh. 2 - People with nail-patella syndrome have poorly...Ch. 2 - Midphalangeal hair hair on top of the middle...Ch. 2 - A man with Huntington disease he is heterozygous...Ch. 2 - Explain why disease alleles for cystic fibrosis CF...Ch. 2 - The following pedigree shows the inheritance of...
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- Refer to question 4. Assuming complete dominance, the F2 generation will show a phenotypic ratio of _______. a.3:1 b.9:1 c. 1:2:1 d. 9:3:3:1arrow_forwardfigure shows the results of a dihybrid cross involving seed shape and seed color. Q. What proportion of the round and yellow F2 progeny from this cross is homozygous at least at one locus?arrow_forwardThe genes for tall vine D and yellow seed G, are dominant over their respective alleles for dwarf d and green g. What phenotypes are expected from each of the following crosses? Include phenotypic and genotypic ratio. Use Punnet square to show the ff. Crosses. a. Heterozygous tall, homozygous yellow X Homozygous Tall, heterozygous yellow. b. Homozygous Dwarf, heterozygous yellow X Heterozygous tall, homozygous greenarrow_forward
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