Chapter 2, Problem 2.79HW

Explanation of Solution

Function definition for “mul3div4()” function:

The implementation for “mul3div4()” function is given below:

//Header file

#include <stdio.h>

#include <assert.h>

#include <limits.h>

//Function definition for divide by power of "2"

int divide_power2(int x, int k)

{

//Determine negation value

int isNegation = x & INT_MIN;

//Check condition

(isNegation && (x = x + (1 << k) - 1));

//Returns value by using "x >> k" that is "x/(2^k)"

return x >> k;

}

//Function definition for mul3div4 function

int mul3div4(int x)

{

//Compute multiply "3"

int m3 = (x << 1) + x;

/* Returns the value of "3 * x/4" by calling function "divide_power2" */

return divide_power2(m3, 2);

}

//Main function

int main(int argc, char* argv[])

{

//Assign the value for "x"

int xValue = 0x87651234;

/* Call function "mul3div4" with checking "x * 3 / 4" value using assert function */

assert(mul3div4(xValue) == xValue * 3 / 4);

return 0;

}

The given code is used to compute the value of “$\text{3}\text{*}\frac{\text{x}}{\text{4}}$”