ORGANIC CHEMISTRY
5th Edition
ISBN: 9781259977596
Author: SMITH
Publisher: MCG
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Question
Chapter 2, Problem 2.69P
Interpretation Introduction
(a)
Interpretation: The given reaction is to be classified as either a proton transfer reaction or a reaction of electrophile and nucleophile. The movement of electrons is to be shown by curved arrows.
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile Lewis base donates an electron pair. It acts as nucleophile. Conjugate base is formed by the loss of a proton from an acid while conjugate acid is formed by the gain of electron by a base.
Interpretation Introduction
(b)
Interpretation: The given reaction is to be classified as either a proton transfer reaction or a reaction of electrophile and nucleophile. The movement of electrons is to be shown by curved arrows.
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile Lewis base donates an electron pair. It acts as nucleophile. Conjugate base is formed by the loss of a proton from an acid while conjugate acid is formed by the gain of electron by the base.
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Students have asked these similar questions
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 2 Solutions
ORGANIC CHEMISTRY
Ch. 2 - a. Which compounds are Bronsted-Lowry acids:...Ch. 2 - a. Draw the conjugate acid of each base:...Ch. 2 - Label each statement as True or False.
a. is the...Ch. 2 - Label the acid and base, and the conjugate acid...Ch. 2 - Decide which compound is the acid and which is the...Ch. 2 - Draw the products formed from the acid-base...Ch. 2 - Which compound in each pair is the stronger acid?...Ch. 2 - Use a calculator when necessary to answer the...Ch. 2 - Rank the conjugate bases of each of group of acids...Ch. 2 - Problem-2.10 Considers two acids: (formic acid,)...
Ch. 2 - Prob. 2.11PCh. 2 - Draw the products of each reaction and determine...Ch. 2 - Prob. 2.13PCh. 2 - Without reference to a pKa table, decide which...Ch. 2 - Rank the labeled H atoms in the following compound...Ch. 2 - Which hydrogen in each molecule is most...Ch. 2 - Which hydrogen in pseudoephedrine, the nasal...Ch. 2 - Which compound in each pair of isomers is the...Ch. 2 - Which compound in each pair is the stronger acid?...Ch. 2 - Glycolic acid, HOCH2CO2H, is the simplest member...Ch. 2 - Explain the apparent paradox. HBr is a stronger...Ch. 2 - The CH bond in acetone, (CH3)2C=O, has a pKa of...Ch. 2 - Acetonitrile (CH3CN) has a pKa of 25, making it...Ch. 2 - For each pair of compounds: [1] Which indicated H...Ch. 2 - Rank the compounds in each group in order of...Ch. 2 - Which proton in each of the following drugs is...Ch. 2 - Which anion A or B is the stronger base? ABCh. 2 - Prob. 2.28PCh. 2 - Problem 2.29
Compounds like amphetamine that...Ch. 2 - Problem 2.30 Which species are Lewis bases?
a. b....Ch. 2 - Which species are Lewis acids?
a. b. c. d.
Ch. 2 - For each reaction, label the Lewis acid and base....Ch. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Label the Lewis acid and base. Use curved arrow...Ch. 2 - 2.36 Propranolol is an antihypertensive agent—that...Ch. 2 - 2.37 Amphetamine is a powerful stimulant of the...Ch. 2 - 2.38 What is the conjugate acid of each base?
a....Ch. 2 - 2.39 What is the conjugate base of each acid?
a....Ch. 2 - 2.40 Draw the products formed from the acid-base...Ch. 2 - Draw the products formed from the acid-base...Ch. 2 - Draw the products of each proton transfer...Ch. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - What is Ka for each compound? Use a calculator...Ch. 2 - What is the pKa for each compound? a. b. c.Ch. 2 - Which of the following bases are strong enough to...Ch. 2 - Which compounds can be deprotonated by OH, so that...Ch. 2 - Draw the products of each reaction. Use the pKa...Ch. 2 - Rank the following compounds in order of...Ch. 2 - 2.51 Rank the following ions in order of...Ch. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - 2.54 The of three bonds is given below.
a. For...Ch. 2 - a. What is the conjugate acid of A? b. What is the...Ch. 2 - 2.56 Draw the structure of a constitutional isomer...Ch. 2 - 2.57 Many drugs are Bronsted-Lowry acids or...Ch. 2 - Dimethyl ether (CH3OCH3) and ethanol (CH3CH2OH)...Ch. 2 - 2.59 Atenolol is a (beta) blocker, a drug used to...Ch. 2 - 2.60 Use the principles in Section 2.5 to label...Ch. 2 - 2.61 Label the three most acidic hydrogen atoms in...Ch. 2 - Prob. 2.62PCh. 2 - 2.63 Classify each compound as a Lewis base, a...Ch. 2 - 2.64 Classify each species as a Lewis acid, a...Ch. 2 - Label the Lewis acid and Lewis base in each...Ch. 2 - 2.66 Draw the products of each Lewis acid-base...Ch. 2 - Prob. 2.67PCh. 2 - 2.68 Answer the following questions about the four...Ch. 2 - Prob. 2.69PCh. 2 - 2.70 Hydroxide can react as a Brønsted-Lowry base...Ch. 2 - 2.71 Answer the following questions about esmolol,...Ch. 2 - 2.72 DBU, is a base we will encounter in...Ch. 2 - 2.73 Molecules like acetamide can be protonated...Ch. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - 2.76 Write a stepwise reaction sequence using...Ch. 2 - Prob. 2.77PCh. 2 - 2.78 Which compound, M or N, is the stronger acid?...
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- 81. a. Propose a mechanism for the following reaction: OH CH2=CHCHC=N b. What is the product of the following reaction? HO H₂O N=CCH2CH2CH OH HO CH3CCH=CH2 H₂O C=N 82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium uliaarrow_forwardFor each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HEarrow_forwardPredicting As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: H₂N O H 1. ? 2. H3O+ If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. 0 If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. فا Explanation Check Click and drag to start drawing a structure.arrow_forward
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