Name these compounds: (a) Na 2 CrO 4 , (b) K 2 HPO 4 , (c) HBr (gas), (d) HBr (in water), (e) Li 2 CO 3 , (f) K 2 Cr 2 O 7 , (g) NH 4 NO 2 , (h) PF 3 , (i) PF 5 , (j) P 4 O 6 , (k) CdI 2 , (l) SrSO 4 , (m) Al(OH) 3 , (n) Na 2 CO 3 · 10H 2 O.

Question

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Answer 1

Textbook Question

Chapter 2, Problem 2.57QP

Name these compounds: (a) Na₂CrO₄, (b) K₂HPO₄, (c) HBr (gas), (d) HBr (in water), (e) Li₂CO₃, (f) K₂Cr₂O₇, (g) NH₄NO₂, (h) PF₃, (i) PF₅, (j) P₄O₆, (k) CdI₂, (l) SrSO₄, (m) Al(OH)₃, (n) Na₂CO₃ · 10H₂O.

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

(g)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

(h)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

(i)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

(j)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

(k)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

(l)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

(m)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

(n)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

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Answer 2

Textbook Question

Chapter 2, Problem 2.57QP

Name these compounds: (a) Na₂CrO₄, (b) K₂HPO₄, (c) HBr (gas), (d) HBr (in water), (e) Li₂CO₃, (f) K₂Cr₂O₇, (g) NH₄NO₂, (h) PF₃, (i) PF₅, (j) P₄O₆, (k) CdI₂, (l) SrSO₄, (m) Al(OH)₃, (n) Na₂CO₃ · 10H₂O.

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

(g)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

(h)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

(i)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

(j)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

(k)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

(l)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

(m)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

(n)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

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Answer 3

Textbook Question

Chapter 2, Problem 2.57QP

Name these compounds: (a) Na₂CrO₄, (b) K₂HPO₄, (c) HBr (gas), (d) HBr (in water), (e) Li₂CO₃, (f) K₂Cr₂O₇, (g) NH₄NO₂, (h) PF₃, (i) PF₅, (j) P₄O₆, (k) CdI₂, (l) SrSO₄, (m) Al(OH)₃, (n) Na₂CO₃ · 10H₂O.

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

(g)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

(h)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

(i)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

(j)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

(k)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

(l)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

(m)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

(n)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

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Answer 4

Textbook Question

Chapter 2, Problem 2.57QP

Name these compounds: (a) Na₂CrO₄, (b) K₂HPO₄, (c) HBr (gas), (d) HBr (in water), (e) Li₂CO₃, (f) K₂Cr₂O₇, (g) NH₄NO₂, (h) PF₃, (i) PF₅, (j) P₄O₆, (k) CdI₂, (l) SrSO₄, (m) Al(OH)₃, (n) Na₂CO₃ · 10H₂O.

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

(g)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

(h)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

(i)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

(j)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

(k)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

(l)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

(m)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

(n)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

(g)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

(h)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

(i)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

(j)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

(k)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

(l)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

(m)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

(n)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

Answer 8

(a)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

The prefixes on each atom indicate the number of those atoms in the compound.
The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
Subscripts are discarded when the numerical charge on cation and anion are equal.
When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.

Answer 13

Answer to Problem 2.57QP

The given compound $Na2CrO4$ is named as Sodium chromate.

Answer 14

Explanation of Solution

$Na2CrO4$ has sodium Na, chromium Cr and oxygen O atoms. According to the nomenclature rules the subscript 2 on Na indicates charge on $CrO4$ therefore anion of this compound is $CrO42−$ and cation is $Na+.$ Hence, the name of $CrO42−$ is chromate and so name of the compound is sodium chromate.

Answer 15

(b)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 20

Answer to Problem 2.57QP

The given compound $K2HPO4$ is named as Potassium hydrogen phosphate.

Answer 21

Explanation of Solution

$K2HPO4$ has potassium K, hydrogen H, phosphorus P and oxygen O atoms. According to the nomenclature rules the subscript 2 on K indicates charge on $HPO4$ therefore anion of this compound is $HPO42−$ and cation is $Na+.$ Hence, the name of $HPO42−$ is Hydrogen phosphate and so name of the compound is Potassium hydrogen phosphate.

Answer 22

(c)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 27

Answer to Problem 2.57QP

The given compound $HBr$ (gas) is named asHydrogen bromide.

Answer 28

Explanation of Solution

$HBr$ has hydrogen H, and Bromine Br atoms. According to the nomenclature rules the subscript 1 on H indicates charge on $Br$ therefore anion of this compound is $Br−$ and cation is $H+.$ Hence, name of $Br−$ is bromide ion and so name of the compound isHydrogen bromide.

Answer 29

(d)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 34

Answer to Problem 2.57QP

The given compound $HBr$ (water) is named ashydrobromic acid.

Answer 35

Explanation of Solution

$HBr$ in water forms acid. Binary acids are named based on the non-metal atom present in them. Hence, name of the compound is given as hydrobromic acid.

Answer 36

(e)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 41

Answer to Problem 2.57QP

The given compound $Li2CO3$ is named as Lithium carbonate.

Answer 42

Explanation of Solution

$Li2CO3$ has Lithium, carbon and oxygen. The subscript 2 on Li indicates charge on $CO3$ . Thus the anion is $CO32−$ and its name is carbonate. Name of the compound is given as Lithium carbonate.

Answer 43

(f)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

Answer 44

(f)

Expert Solution

Answer 45

(f)

Expert Solution

Answer 46

Expert Solution

Answer 47

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 48

Answer to Problem 2.57QP

The given compound $K2Cr2O7$ is named as Potassium dichromate.

Answer 49

Explanation of Solution

$K2Cr2O7$ has Potassium, chromium and oxygen. The subscript 2 on K indicates charge on $Cr2O7$ . Thus the anion is $Cr2O72−$ and its name is dichromate with reference to table 2.3 in the text book. Name of the compound is given as Potassium dichromate.

Answer 50

(g)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

Answer 51

(g)

Expert Solution

Answer 52

(g)

Expert Solution

Answer 53

Expert Solution

Answer 54

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 55

Answer to Problem 2.57QP

The given compound $NH4NO2$ is named as ammonium nitrite.

Answer 56

Explanation of Solution

$NH4NO2$ has Nitrogen, Hydrogen and oxygen. The compound has cation $NH4+$ and anion $NO2−$ and their names are ammonium ion and nitrite ion respectively. Hence, name of the compound is given asammonium nitrite.

Answer 57

(h)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

Answer 58

(h)

Expert Solution

Answer 59

(h)

Expert Solution

Answer 60

Expert Solution

Answer 61

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 62

Answer to Problem 2.57QP

The given compound $PF3$ is named as phosphorus trifluoride.

Answer 63

Explanation of Solution

$PF3$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Three F atoms are bonded to P and F gets the name trifluoride. According to nomenclature rules the compound is named as phosphorus trifluoride.

Answer 64

(i)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

Answer 65

(i)

Expert Solution

Answer 66

(i)

Expert Solution

Answer 67

Expert Solution

Answer 68

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 69

Answer to Problem 2.57QP

The given compound $PF5$ is named as phosphorus pentafluoride.

Answer 70

Explanation of Solution

$PF5$ has phosphorus and Fluorine. It is not an ionic compound but covalent compound. F has greater electronegativity than P and hence its name should end with ‘ide’. Five F atoms are bonded to P and F gets the name pentafluoride. According to nomenclature rules the compound is named as phosphorus pentafluoride.

Answer 71

(j)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

Answer 72

(j)

Expert Solution

Answer 73

(j)

Expert Solution

Answer 74

Expert Solution

Answer 75

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 76

Answer to Problem 2.57QP

The given compound $P4O6$ is named as tetraphosphorus hexoxide.

Answer 77

Explanation of Solution

$P4O6$ has phosphorus and oxygen. It is not an ionic compound but covalent compound. O has greater electronegativity than P and hence its name should end with ‘ide’. SixO atoms are bonded to P and O gets the name hexoxide. 4 P atoms are bonded to O and hence according to nomenclature rules the compound is named as tetraphosphorus hexoxide.

Answer 78

(k)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

Answer 79

(k)

Expert Solution

Answer 80

(k)

Expert Solution

Answer 81

Expert Solution

Answer 82

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 83

Answer to Problem 2.57QP

The given compound $CdI2$ is named as Cadmium iodide.

Answer 84

Explanation of Solution

$CdI2$ has cadmium and iodine. The subscript 2 on I indicates charge on Cd thus $Cd2+$ is the cation. The subscript 1 on Cd indicates charge on I thus $I−$ is the cation and name of $I−$ is iodide ion. Hence name of the compound is cadmium iodide.

Answer 85

(l)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

Answer 86

(l)

Expert Solution

Answer 87

(l)

Expert Solution

Answer 88

Expert Solution

Answer 89

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 90

Answer to Problem 2.57QP

The given compound $SrSO4$ is named as Strontium sulfate.

Answer 91

Explanation of Solution

$SrSO4$ has Strontium, Sulfur and oxygen. The compound has cation $Sr2+$ and anion $SO42−$ and their names are strontium ion and sulfate ion respectively. Hence name of the compound is strontium sulfate.

Answer 92

(m)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

Answer 93

(m)

Expert Solution

Answer 94

(m)

Expert Solution

Answer 95

Expert Solution

Answer 96

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 97

Answer to Problem 2.57QP

The given compound $Al(OH)3$ is named as Aluminum hydroxide.

Answer 98

Explanation of Solution

The compound $Al(OH)3$ has cation $Al3+$ and anion $OH−$ and their names are Aluminum ion and hydroxide ion are respectively. Hence name of the compound isAluminum hydroxide.

Answer 99

(n)

Expert Solution

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

Answer 100

(n)

Expert Solution

Answer 101

(n)

Expert Solution

Answer 102

Expert Solution

Answer 103

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer to part (a).

Answer 104

Answer to Problem 2.57QP

The given compound $Na2CO3.10H2O$ is named as Sodium carbonate decahydrate.

Answer 105

Explanation of Solution

With reference to table 2.3 in the text book, anions and cations formed by various elements are named.

The compound $Na2CO3.10H2O$ has cation $Na+$ and anion $CO32−$ and the names of the ions are sodium ion and carbonate ion respectively. 10 water molecules are bonded to the molecule. Hence name of the compound is sodium carbonate decahydrate.

Answer 106

Ch. 2.1 - The atoms of elements A (blue) and B (orange) form...Ch. 2.3 - How many protons, neutrons, and electrons are in...Ch. 2.3 - Review of Concepts What is the atomic number of an...Ch. 2.4 - In viewing the periodic table, do chemical...Ch. 2.5 - Review of Concepts what does S8 signify? How does...Ch. 2.6 - Write the empirical formula for caffeine...Ch. 2.6 - Prob. 4PE Ch. 2.6 - Prob. 1RC Ch. 2.7 - Name the following compounds: (a) PbO and (b)...Ch. 2.7 - Prob. 6PE

Name these compounds: (a) Na 2 CrO 4 , (b) K 2 HPO 4 , (c) HBr (gas), (d) HBr (in water), (e) Li 2 CO 3 , (f) K 2 Cr 2 O 7 , (g) NH 4 NO 2 , (h) PF 3 , (i) PF 5 , (j) P 4 O 6 , (k) CdI 2 , (l) SrSO 4 , (m) Al(OH) 3 , (n) Na 2 CO 3 · 10H 2 O.

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Answer to Problem 2.57QP

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