
Concept explainers
(a)
To determine: The four different conjugate bases that would be formed by the deprotonation of the four different
Interpretation: The four different conjugate bases that would be formed by the deprotonation of the four different
Concept introduction: The delocalization of electrons due to presence of lone pair and double bond is called resonating structure. The structure is more stable if the resonating structures are more. When an acid donates a proton the species formed is known as conjugate base and when the base accepts a proton the species formed is known as conjugate acid.
(b)
To determine: The comparison between the stabilities of the resulting conjugate bases and the most acidic
Interpretation: The stabilities of the resulting conjugate bases are to be compared and the most acidic
Concept introduction: The acidity and basicity of a compound is influenced by the resonance. The amount of stability depends on the delocalization of the charge through the resonance.
(c)
To determine: The comparison between the most stable conjugate bases of ascorbic acid and acetic acid and an explanation corresponding to the fact that the two compounds have similar acidities even though ascorbic acid lacks carboxylic group.
Interpretation: The most stable conjugate bases of ascorbic acid and acetic acid are to be compared and an explanation corresponding to the fact that the two compounds have similar acidities even though ascorbic acid lacks carboxylic group is to be explained.
Concept introduction: The acidity and basicity of a compound is influenced by the resonance. The amount of stability depends on the delocalization of the charge through the resonance.

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Chapter 2 Solutions
ORGANIC CHEMISTRY
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- CUE COLUMN NOTES (A. Determine Stereoisomers it has ⑤ Identify any meso B compounds cl Br cl -c-c-c-c-¿- 1 CI C- | 2,4-Dichloro-3-bromopentanearrow_forwardThe acid-base chemistry of both EDTA and EBT are important to ensuring that the reactions proceed as desired, thus the pH is controlled using a buffer. What percent of the EBT indicator will be in the desired HIn2- state at pH = 10.5. pKa1 = 6.2 and pKa2 = 11.6 of EBTarrow_forwardWhat does the phrase 'fit for purpose' mean in relation to analytical chemistry? Please provide examples too.arrow_forward
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