Explanation Given Info: The initial velocity of ball is 8.00 m / s and the ball is thrown from the height of 30.0 m . The value of the acceleration due to gravity is 9.8 m / s 2 . The third equation of motion is, ( v f ) 2 = ( v i ) 2 + 2 g h Here, v f is the final velocity. v i is the initial velocity. g is the acceleration due to gravity. h is the height Substitute 8.00 m / s for v i , 9.8 m / s 2 for g and 30.0 m for h in the above equation. ( v f ) 2 = ( 8.00 m / s ) 2 + 2 ( 9.8 m / s 2 ) ( 30.0 m ) = ( 8.00 m / s ) 2 + 2 ( 9.8 m / s 2 ) ( 30

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 2, Problem 2.51P

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The time interval after which the ball strikes the ground.

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The time interval after which the ball strikes the ground.

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