Concept explainers
(a)
Interpretation:
The value of vapor pressure at T = 185 °C should be determined by using two-point linear interpolation.
Concept introduction:
Linear interpolation equation,
If the two known values are (x1 , y1 ) and (x2 , y2 ), then the y value for some point x is,
(b)
Interpretation:
The vapor pressure at 148.2 °C and the percentage error considering given value should be determined along with the reason for expecting the error which is associated with part (a) to be significantly less than part (b).
Concept introduction:
Linear interpolation equation,
If the two known values are (x1, y1) and (x2, y2), then the y value for some point x is,
The formula to calculate percentage error is,
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ELEMENTARY PRINCIPLES OF CHEM. PROCESS.
- Comelli and Francesconi examined mixtures of propionic acid with various other organic liquids at 313.15 K (F. Comelli and R. Francesconi, J. Chem. Eng. Data 41, 101 (1996)). They report the excess volume of mixing propionic acid with tetrahydropyran (THP, oxane) as VE = x1x2{a0 + a1(x1 − x2)}, where x1 is the mole fraction of propionic acid, x2 that of THP, a0 = −2.4697 cm3 mol−1, and a1 = 0.0608 cm3 mol−1. The density of propionic acid at this temperature is 0.971 74 g cm−3; that of THP is 0.863 98 g cm−3. (a) Derive an expression for the partial molar volume of each component at this temperature. (b) Compute the partial molar volume for each component in an equimolar mixture.arrow_forward3.arrow_forwardPlease help with (c)arrow_forward
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- Iron(II) chloride (melting point 677 °C) and potassium chloride (melting point 776 °C) form the compounds KFeCl3 and K2FeCl4 at elevated temperatures. KFeCl3 melts congruently at 399 °C and K2FeCl4 melts incongruently at 380 °C. Eutectics are formed with compositions x = 0.38 (melting point 351 °C) and x = 0.54 (melting point 393 °C), where x is the mole fraction of FeCl2. The KCl solubility curve intersects the A curve at x = 0.34. Sketch the phase diagram. State the phases that are in equilibrium when a mixture of composition x = 0.36 is cooled from 400 °C to 300 °C.arrow_forwardPlease write solution on paper, thank you. No typing, it's hard to follow. I'll give positive feedbackarrow_forwardPlease help with (c)arrow_forward
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