(a) Interpretation: The units of 70.5 and 8.27×10-7 should be calculated. Concept introduction: The density of a fluid is given by the empirical equation, ρ = 70.5 exp ( 8.27 × 10 − 7 P ) ρ = Density , P = Pressure It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Question

An 8-foot ion exchange bed needs to be backwashed with water to remove impurities. The particles have a density of 1.24 g/cm³ and an average size of 1.1 mm. Calculate: a. The minimum fluidization velocity using water at 30°C? b. The velocity required to expand the bed by 30%? Assumptions: The ion exchange bed particles are spherical (sphericity = 1.1), and the minimum fluidization porosity (ɛM) is 0.3. Notes: At 30°C, the viscosity (μ) of water is 0.797 cP, and the density (ρ) is 0.995 g/cm³.

Answer 1

Question

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Expert Solution & Answer

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02:35

Students have asked these similar questions

An 8-foot ion exchange bed needs to be backwashed with water to remove impurities. The particles have a density of 1.24 g/cm³ and an average size of 1.1 mm. Calculate: a. The minimum fluidization velocity using water at 30°C? b. The velocity required to expand the bed by 30%? Assumptions: The ion exchange bed particles are spherical (sphericity = 1.1), and the minimum fluidization porosity (ɛM) is 0.3. Notes: At 30°C, the viscosity (μ) of water is 0.797 cP, and the density (ρ) is 0.995 g/cm³.

fluidized bed reactor uses a solid catalyst with a particle diameter of 0.25 mm, a bulk density of 1.50 g/mL, and a sphericity of 0.90. Under packed bed conditions, the porosity is 0.35, and the bed height is 2 m. The gas enters from the bottom of the reactor at a temperature of 600°C, with a viscosity of 0.025 cP and a density of 0.22 lb/ft³. At minimum fluidization, the porosity reaches 0.45. Calculate: a. The minimum superficial velocity (VM) of the gas entering the fluidized column. b. The bed height if V = 2 VM c. The pressure drop under conditions where V =2.5 VM

A fluidized bed reactor uses a solid catalyst with a particle diameter of 0.25 mm, a bulk density of 1.50 g/mL, and a sphericity of 0.90. Under packed bed conditions, the porosity is 0.35, and the bed height is 2 m. The gas enters from the bottom of the reactor at a temperature of 600°C, with a viscosity of 0.025 cP and a density of 0.22 lb/ft³. At minimum fluidization, the porosity reaches 0.45. Calculate: a. The minimum superficial velocity (VM) of the gas entering the fluidized column. b. The bed height if V = 2 VM c. The pressure drop under conditions where V =2.5 VM

Answer 2

Question

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Expert Solution & Answer

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See solution

Check out sample textbook solution

02:35

Answer 3

Question

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Expert Solution & Answer

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Check out sample textbook solution

02:35

Answer 4

Question

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Expert Solution & Answer

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See solution

Check out sample textbook solution

02:35

Answer 5

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Answer 6

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Answer 7

Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Answer 9

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Answer 10

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Answer 11

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

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Answer 16

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Answer 17

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Answer 18

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Answer 19

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Answer 20

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Answer 21

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Answer 22

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Answer 23

Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P

(b) Interpretation: The density for a pressure of 9.00×106 N/m2 should be calculated. Concept introduction: The density of a fluid is given by the empirical equation, ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

(c) Interpretation: A formula for ρ (g/cm3) as a function of P (N/m2) should be derived. Concept introduction: The density of a fluid is given by the empirical equation, ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

Chapter 2 Solutions

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

ρ = 70.5 exp (8.27 × 10−7 P)ρ = Density, P = Pressure