Chapter 2, Problem 2.30P

Interpretation Introduction

(a)

Interpretation:

The units of 70.5 and 8.27×10-7 should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

$\begin{array}{l}\rho =70.5\exp \left(8.27\times {10}^{-7}P\right)\\ \rho =\text{Density},P=\text{Pressure}\end{array}$

It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal.

Interpretation Introduction

(b)

Interpretation:

The density for a pressure of 9.00×10⁶ N/m² should be calculated.

Concept introduction:

The density of a fluid is given by the empirical equation,

$\begin{array}{l}\rho =70.5\exp \left(8.27\times {10}^{-7}P\right)\\ \rho =\text{Density},P=\text{Pressure}\end{array}$

Interpretation Introduction

(c)

Interpretation:

A formula for ρ (g/cm³) as a function of P (N/m²) should be derived.

Concept introduction:

The density of a fluid is given by the empirical equation,

$\begin{array}{l}\rho =70.5\exp \left(8.27\times {10}^{-7}P\right)\\ \rho =\text{Density,}P=\text{Pressure}\end{array}$