Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 2, Problem 22E
Interpretation Introduction

(a)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as a universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Expert Solution
Check Mark

Answer to Problem 22E

The value of 65in. is equal to 165.1cm.

Explanation of Solution

The value of 1in.=2.54cm.

The conversion factor can be written as 2.54cm1in..

The conversion of 65in. into cm is given as,

65in.=2.54cm1in.×65in = 165.1cm

Conclusion

The value of 65in. is equal to 165.1cm.

Interpretation Introduction

(b)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as an universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Expert Solution
Check Mark

Answer to Problem 22E

The value of 65lb is equal to 29510g.

Explanation of Solution

The value of 1lb=454g.

The conversion factor can be written as 454g1lb.

The conversion of 65lb into g is given as,

65lb=454g1lb×65lb=29510g

Conclusion

The value of 65lb is equal to 29510g.

Interpretation Introduction

(c)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as an universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Expert Solution
Check Mark

Answer to Problem 22E

The value of 65mL is equal to 0.0687qt.

Explanation of Solution

The value of 1qt=946mL.

The conversion factor can be written as 1qt946mL.

The conversion of 65mL into qt is given as,

65mL=1qt946mL×65mL=0.0687qt.

Conclusion

The value of 65mL is equal to 0.0687qt.

Interpretation Introduction

(d)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as an universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Expert Solution
Check Mark

Answer to Problem 22E

The value of 6.50×103s is equal to 6.50×103sec.

Explanation of Solution

The value of 1sec=1.00s.

The conversion factor can be written as 1sec1.00s.

The conversion of 6.50×103s into sec is given as,

6.50×103s=1sec1.00s×6.50×103s=6.50×103sec

Conclusion

The value of 6.50×103s is equal to 6.50×103sec.

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Chapter 2 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 2 - Prob. 2.11CECh. 2 - Prob. 2.12CECh. 2 - Prob. 2.13CECh. 2 - Prob. 2.14CECh. 2 - Prob. 2.15CECh. 2 - Prob. 2.16CECh. 2 - Prob. 2.17CECh. 2 - Prob. 2.18CECh. 2 - Prob. 1KTCh. 2 - Prob. 2KTCh. 2 - Prob. 3KTCh. 2 - Prob. 4KTCh. 2 - Prob. 5KTCh. 2 - Prob. 6KTCh. 2 - Prob. 7KTCh. 2 - Prob. 8KTCh. 2 - Prob. 9KTCh. 2 - Prob. 10KTCh. 2 - Prob. 11KTCh. 2 - Prob. 12KTCh. 2 - Prob. 13KTCh. 2 - Prob. 14KTCh. 2 - Prob. 15KTCh. 2 - Prob. 16KTCh. 2 - Prob. 17KTCh. 2 - Prob. 18KTCh. 2 - Prob. 19KTCh. 2 - Prob. 20KTCh. 2 - Prob. 21KTCh. 2 - Prob. 22KTCh. 2 - Prob. 23KTCh. 2 - Prob. 24KTCh. 2 - Prob. 25KTCh. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Prob. 54ECh. 2 - Prob. 55ECh. 2 - Prob. 56ECh. 2 - Prob. 57ECh. 2 - Prob. 58ECh. 2 - Prob. 59ECh. 2 - Prob. 60ECh. 2 - Prob. 61ECh. 2 - Prob. 62ECh. 2 - Prob. 63ECh. 2 - Prob. 64ECh. 2 - Prob. 65ECh. 2 - Prob. 66ECh. 2 - Prob. 67ECh. 2 - Prob. 68ECh. 2 - Prob. 69ECh. 2 - Prob. 70ECh. 2 - Prob. 71ECh. 2 - Prob. 72ECh. 2 - Prob. 73ECh. 2 - Prob. 74ECh. 2 - Prob. 75ECh. 2 - Prob. 76ECh. 2 - Prob. 77ECh. 2 - Prob. 78ECh. 2 - Prob. 79ECh. 2 - Prob. 80ECh. 2 - Prob. 81ECh. 2 - Prob. 82ECh. 2 - Prob. 83ECh. 2 - Prob. 84ECh. 2 - Prob. 85ECh. 2 - Prob. 86ECh. 2 - Prob. 87ECh. 2 - Prob. 88ECh. 2 - Prob. 89ECh. 2 - Prob. 90ECh. 2 - Prob. 91ECh. 2 - Prob. 92ECh. 2 - Prob. 93ECh. 2 - Prob. 94ECh. 2 - Prob. 95ECh. 2 - Prob. 96ECh. 2 - Prob. 1STCh. 2 - Prob. 2STCh. 2 - Prob. 3STCh. 2 - Prob. 4STCh. 2 - Prob. 5STCh. 2 - Prob. 6STCh. 2 - Prob. 7STCh. 2 - Prob. 8STCh. 2 - Prob. 9STCh. 2 - Prob. 10STCh. 2 - Prob. 11STCh. 2 - Prob. 12STCh. 2 - Prob. 13STCh. 2 - Prob. 14ST
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