International Edition---engineering Mechanics: Statics 4th Edition
4th Edition
ISBN: 9781305856240
Author: Pytel
Publisher: Cengage
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Chapter 2, Problem 2.28P
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Chapter 2 Solutions
International Edition---engineering Mechanics: Statics 4th Edition
Ch. 2 - Â Which of the force system shown are equivalent...Ch. 2 - Two men are trying to roll the boulder by applying...Ch. 2 - The magnitudes of the three forces applied to the...Ch. 2 - Replace the three forces by a single equivalent...Ch. 2 - Replace the three forces with a single equivalent...Ch. 2 - The forces P1=110lb,P2=200lb, and P3=150lb are...Ch. 2 - Determine the magnitudes of the three forces...Ch. 2 - The magnitudes of the three forces acting on the...Ch. 2 - Determine the three forces acting on the plate...Ch. 2 - The force R is the resultant of the forces P1,P2,...
Ch. 2 - Knowing that the resultant of the two forces is...Ch. 2 - Knowing that the forces P and Q are equivalent to...Ch. 2 - Three ropes support the weight at A. The tension...Ch. 2 - Find the forces Q1,Q2, and Q3 so that the two...Ch. 2 - The man exerts a force P of magnitude 40 1b on the...Ch. 2 - The three forces acting on the beam can be...Ch. 2 - The trapdoor is held in the horizontal plane by...Ch. 2 - Replace the three forces acting on the guy wires...Ch. 2 - The horizontal boom carries the weight W=108lb at...Ch. 2 - The three forces, each of magnitude F, are applied...Ch. 2 - Determine the resultant force R that is equivalent...Ch. 2 - Determine the magnitude and sense of the moment of...Ch. 2 - Find the magnitude and sense of the moment of the...Ch. 2 - Two forces of magnitude P each act on the beam....Ch. 2 - A force P in the xy-plane acts on the triangular...Ch. 2 - A force P in the xy-plane acts on the triangular...Ch. 2 - Determine the moment of the force F=9i+18jlb about...Ch. 2 - Given that T=43kN and W=38kN, determine the...Ch. 2 - A moment of 50lbft about O is required to loosen...Ch. 2 - Determine the moment of the force F about point A...Ch. 2 - The resultant of the two forces shown has a line...Ch. 2 - The tow truck's front wheels will be lifted off...Ch. 2 - The force F acts on the gripper of the robot arm....Ch. 2 - Given that the magnitude of the moment of P about...Ch. 2 - The magnitude of the force P is 160 N. Determine...Ch. 2 - The magnitude of the force Q Determine the moments...Ch. 2 - The magnitude of the moment of force P about point...Ch. 2 - The magnitude of the force P is 50 kN. Determine...Ch. 2 - Determine the combined moment of the two forces...Ch. 2 - Find the combined moment of the forces P and Q...Ch. 2 - The wrench is used to tighten a nut on the wheel....Ch. 2 - The magnitudes of the two forces shown are P=16lb...Ch. 2 - The moment of the force F=50i100j70klb about point...Ch. 2 - Determine the magnitude of the moment of the 150-N...Ch. 2 - The combined moment of the two forces, each of...Ch. 2 - The force F=2i12j+5klb acts along the line AB....Ch. 2 - Calculate the combined moment of the three forces...Ch. 2 - Determine the moment of the force F=40i+30j+20kkN...Ch. 2 - Determine the moment of the 400-lb force about...Ch. 2 - The magnitude of the force F is 55 lb. Calculate...Ch. 2 - The force F=18i12j+10kN is applied to the gripper...Ch. 2 - The legs of the tripod have equal lengths. The...Ch. 2 - Determine the moment of the force F=40i8j+5kN...Ch. 2 - To lift the table without tilting, the combined...Ch. 2 - The combined moment of the three forces is zero...Ch. 2 - The trap door is held open by the rope AB. If the...Ch. 2 - The forces P and Q act on the handles of the...Ch. 2 - The magnitude of the force P is 360 N. Determine...Ch. 2 - The combined moment of P and the 20-lb force about...Ch. 2 - Determine the magnitude of the force F given that...Ch. 2 - The force F of magnitude 200Â NÂ isÂ...Ch. 2 - Calculate the moment of the force P about the axis...Ch. 2 - The force systems in Figs. (a) and (b) have the...Ch. 2 - The force F=F(0.6i+0.8j)kN is applied to the frame...Ch. 2 - Determine the combined moment of the four forces...Ch. 2 - The flexible shaft AB of the wrench is bent into a...Ch. 2 - The magnitude of the force F is 180 lb. Find the...Ch. 2 - Which of the systems are equivalent to the couple...Ch. 2 - Which of the systems are equivalent to the couple...Ch. 2 - If the couple applied to the steering wheel is to...Ch. 2 - Determine the magnitude of the couple shown.Ch. 2 - Determine the couple-vector that is equivalent to...Ch. 2 - Calculate the combined moment of the couple C and...Ch. 2 - Determine the couple-vector that is equivalent to...Ch. 2 - The two forces of magnitude F=30kN form a couple....Ch. 2 - The couple acts on the handles of a steering...Ch. 2 - The force system acting on the plate is equivalent...Ch. 2 - A couple of magnitude 3601b ft is applied about...Ch. 2 - The arm ABCD of the industrial robot lies in a...Ch. 2 - The figure shows one-half of a universal coupling...Ch. 2 - The steering column of the rack-and-pinion...Ch. 2 - Which of the systems are equivalent to the...Ch. 2 - A 15-lb force acts at point A on the high-pressure...Ch. 2 - The bracket, which is fastened to a wall by anchor...Ch. 2 - Replace the three forces applied to the beam by an...Ch. 2 - Replace the two forces shown by a force-couple...Ch. 2 - The figure shows a schematic of a torsion-bar...Ch. 2 - Replace the 250-N force with an equivalent...Ch. 2 - The magnitude of the force F acting at point A on...Ch. 2 - Replace the force-couple system acting on the pipe...Ch. 2 - (a) Replace the force F=2800i+1600j+3000klb acting...Ch. 2 - Determine the force-couple system, with the force...Ch. 2 - Replace the force F and the couple C with an...Ch. 2 - The moment of the force P about the axis AB is...Ch. 2 - Replace the force and the couple shown with an...Ch. 2 - The tensions in the cables supporting the pole are...Ch. 2 - The force acting at A is F=10i+20j5kkN. Knowing...Ch. 2 - The magnitude of the moment of the force P about...Ch. 2 - Calculate the couple-vector formed by the two...Ch. 2 - The magnitudes of the force P and couple C are...Ch. 2 - The resultant force of the three cable tensions...Ch. 2 - The force-couple system shown is equivalent to the...Ch. 2 - Replace the two forces shown with an equivalent...Ch. 2 - The three forces of magnitude P can be replaced by...Ch. 2 - Knowing that the two forces shown can be replaced...Ch. 2 - The trapdoor is held in the position shown by two...Ch. 2 - The force system consists of the force...Ch. 2 - The force system shown can be replaced with a...
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- 1. 1.25 m³ of saturated liquid water at 225°C is expanded isothermally in a closed system until its quality is 75 percent. Determine the total work produced by this expansion, in kJ.arrow_forwardAn undamped single-degree-of-freedom system is subjected to dynamic excitation as shown in Figure 1.• System properties: m = 1, c = 0, k = (6π)2.• Force excitation: p(t) = posin(ωt) where po = 9 and ω = 2π.• Initial conditions: u(t = 0) = 0 and ̇u(t = 0) = 0.Please, complete Parts (a) through (d) using any computational tool of your preference. The preferred toolis MATLAB. Print and turn in a single pdf file that will include your code/calculations and your plots.(a) Generate the solution using a linear interpolation of the load over each time step (note that hereyou can use the undamped coefficients). Plot the displacement response for the first 4 seconds andcompare to the exact closed form solution. Repeat using the following time step sizes, ∆t = 0.01,0.05, 0.15, 0.20 seconds. Include the closed form solution and the solutions for different ∆t values in asingle plot. Please, provide your observations by comparing the closed form solution with the solutionsderived using the four…arrow_forwardAssume multiple single degree of freedom systems with natural periods T ∈ [0.05, 2.00] seconds with in-crement of period dT = 0.05 seconds. Assume three cases of damping ratio: Case (A) ξ = 0%; Case (B)ξ = 2%; Case (C) ξ = 5%. The systems are initially at rest. Thus, the initial conditions are u(t = 0) = 0 anḋu(t = 0) = 0. The systems are subjected to the base acceleration that was provided in the ElCentro.txt file(i.e., first column). For the systems in Case (A), Case (B), and Case (C) and for each natural period computethe peak acceleration, peak velocity, and peak displacement responses to the given base excitation. Please,use the Newmark method for β = 1/4 (average acceleration) to compute the responses. Create threeplots with three lines in each plot. The first plot will have the peak accelerations in y-axis and the naturalperiod of the system in x-axis. The second plot will have the peak velocities in y-axis and the natural periodof the system in x-axis. The third plot will have…arrow_forward
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- Experiment تكنولوجيا السيارات - Internal Forced convenction Heat transfer Air Flow through Rectangular Duct. objective: Study the convection heat transfer of air flow through rectangular duct. Valve Th Top Dead Centre Exhaust Valve Class CP. N; ~ RIVavg Ti K 2.11 Te To 18.8 21.3 45.8 Nath Ne Pre Calculations:. Q = m cp (Te-Ti) m: Varg Ac Acca*b Q=hexp As (Ts-Tm) 2 2.61 18.5 20.846.3 Tm = Te-Ti = 25 AS-PL = (a+b)*2*L Nu exp= Re-Vavy D heep Dh k 2ab a+b Nu Dh the- (TS-Tm) Ts. Tmy Name / Nu exp Naxe بب ارتدان العشريarrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findarrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forward
- Procedure: 1- Cartesian system, 2D3D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D ∑Fx=0 ∑Fy=0 ∑Fz=0 ∑Mx=0 ∑My=0 ΣMz=0 2D ΣFx=0 ΣFy=0 ΣMz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of thearrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
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