MATLAB: A Practical Introduction to Programming and Problem Solving
5th Edition
ISBN: 9780128154793
Author: Stormy Attaway Ph.D. Boston University
Publisher: Elsevier Science
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Chapter 2, Problem 2.1P
To determine
To find:
The output of the following sequence of statements and expressions, and verify them.
pvec = 3:2:10
pvec(2) = 15
pvec(7) = 33
pvec([2:4 7])
linspace(5, 11, 3)
logspace(2, 4, 3)
Expert Solution & Answer
Answer to Problem 2.1P
Solution:
The output of the following sequence of statements and expressions:
“pvec = 3:2:10”, “pvec(2) = 15” “pvec(7) = 33”, “pvec([2:4 7])”, “linspace(5, 11, 3)”, and “logspace(2, 4, 3)” are “pvec = 3 5 7 9”, “pvec = 3 15 7 9 0 0 33”, “ans = 15 7 9 33”, “ans = 5 8 11”, and “ans = 100 1000 10000” respectively.
Explanation of Solution
Consider the following statement,
pvec = 3:2:10
The statement will generate the sequence of number from 3 to 10 in increment of 2.
So, the output is “pvec = 3 5 7 9”.
Consider the following statement,
pvec(2) = 15
The expression replaces the second term of the sequence of “pvec” with “15” and then displays sequence.
So, the output is “pvec = 3 15 7 9”.
Consider the following statement,
pvec(7) = 33
The expression replaces the seventh term of the sequence of “pvec” with “33” and then displays sequence. Since, the values of the 5th and the 6th terms are not allotted, so these terms are allotted with zero.
So, the output is “pvec = 3 15 7 9 0 0 33”.
Consider the following statement,
pvec([2:4 7])
The expression displays the values placed 2nd to 4th and then 7th from the sequence.
So, the output is “ans = 15 7 9 33”.
Consider the following statement,
linspace(5, 11, 3)
The expression generates three values that are equally spaced from 5 to 11.
So, the output is “ans = 5 8 11”.
And, consider the following statement,
logspace(2, 4, 3)
The expression generates three values that are equal to
So, the output is “ans = 100 1000 10000”.
The
MATLAB Code:
clc
clear all
close all
pvec = 3:2:10
% Define the instruction to generate the sequence of number from 3 to 10 in increment of 2.
pvec(2) = 15
% Define the instruction in which the expression replaces the second term of the sequence of “pvec” with “15” and then displays sequence.
pvec(7) = 33
% Define the instruction in which the expression replaces the seventh term of the sequence of “pvec” with “33” and then displays sequence. Since, the values of the 5th and the 6th terms are not allotted, so these terms are allotted with zero.
pvec([2:4 7])
% Define the instruction in which the expression displays the values placed 2nd to 4th and then 7th from the sequence.
linspace(5, 11, 3)
% Define the instruction in which the expression generates three values that are equally spaced from 5 to 11.
logspace(2, 4, 3)
% Define the instruction in which the expression generates three values that are equal to 10^n, here n = 2, 3, 4.
Save the MATLAB script with name, chapter2_54793_2_1P.m in the current folder. Execute the script by typing the script name at the command window to find the answer of the given following sequence of statements and expressions.
Result:
Therefore, the output of the following sequence of statements and expressions:
“pvec = 3:2:10”, “pvec(2) = 15” “pvec(7) = 33”, “pvec([2:4 7])”, “linspace(5, 11, 3)”, and “logspace(2, 4, 3)” are “pvec = 3 5 7 9”, “pvec = 3 15 7 9 0 0 33”, “ans = 15 7 9 33”, “ans = 5 8 11”, and “ans = 100 1000 10000” respectively.
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Chapter 2 Solutions
MATLAB: A Practical Introduction to Programming and Problem Solving
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5E
Ch. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50E
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