MATLAB: A Practical Introduction to Programming and Problem Solving
MATLAB: A Practical Introduction to Programming and Problem Solving
5th Edition
ISBN: 9780128154793
Author: Stormy Attaway Ph.D. Boston University
Publisher: Elsevier Science
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Chapter 2, Problem 2.5P
To determine

To find:

The value of the expressions A.*B, A*B and B*A by hand and then verify the results in MATLAB.

Expert Solution & Answer
Check Mark

Answer to Problem 2.5P

Solution:

The instruction for the sum of the series 1+12+13+14+15+... is

“sum(1./n)”.

Explanation of Solution

The given matrices are,

A=[1433]

And,

B=[1210]

Substitute [1433] for A and [1210] for B in the expression “A.*B”.

A.*B=[1433].*[1210]=[1×14×23×13×0]=[1830]

Substitute [1433] for A and [1210] for B in the expression “A*B”.

A*B=[1433]*[1210]=[(1×1)+(4×1)(1×2)+(4×0)(3×1)+(3×1)(3×2)+(3×0)]=[3206]

Similarly substitute [1433] for A and [1210] for B in the expression “B*A”.

B*A=[1210]*[1433]=[(1×1)+(2×3)(1×4)+(2×3)(1×1)+(0×3)(1×4)+(0×3)]=[71014]

Now, verifying the expression output by using MATLAB command.

MATLAB Code:

clc

clear all

close all

A = [1 4;3 3]

% Define the command to get the matrix “A”.

B = [1 2;-1 0]

% Define the command to get the matrix “B”.

A.*B

% Define the command to get the output of the expression “A.*B”.

A*B

% Define the command to get the output of the expression “A*B”.

B*A

% Define the command to get the output of the expression “B*A”.

Save the MATLAB script with name, chapter2_54793_2_5P.m in the current folder. Execute the script by typing the script name at the command window to find the value of the expressions A.*B, A*B and B*A by hand and then verify the results in MATLAB.

Result:

MATLAB: A Practical Introduction to Programming and Problem Solving, Chapter 2, Problem 2.5P , additional homework tip  1

MATLAB: A Practical Introduction to Programming and Problem Solving, Chapter 2, Problem 2.5P , additional homework tip  2

Therefore, the value of the expressions A.*B, A*B, and B*A is [1830], [3206], and [71014] respectively.

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