(a)
Interpretation:
The coloured boxes that represent four non-metal elements are to be identified.
Concept introduction:
The periodic table is an arrangement of elements according to their properties,
The characteristic properties of non-metals are as follows:
1. Non-metals, unlike metals, can be solid, liquid or gas.
2. Non-metal oxides are acidic in nature.
3. Non-metals are poor conductors of heat and electricity.
4. Non-metals have a tendency to gain electrons to form anions.
5. Non-metals are non-malleable.
6. Non-metals are not ductile.
7. Non-metals do not exhibit sonority.
(b)
Interpretation:
The coloured boxes that represent two metal elements are to be identified.
Concept introduction:
The periodic table is an arrangement of elements according to their properties, atomic number, and electronic configurations.
The characteristic properties of metals are as follows:
1. Metals are hard and shiny in appearance. Except for mercury, all metals are solid.
2. Metallic oxides are basic in nature.
3. Metals are good conductors of heat and electricity
4. Metals have a tendency to lose electrons to form cations.
5. Metals are malleable. They can be beaten into thin sheets
6. Metals are ductile. They can be drawn into wires.
7. Metals exhibit sonority.
(c)
Interpretation:
The coloured boxes that represent three elements that are gaseous at room temperature are to be identified.
Concept introduction:
A periodic table is an arrangement of elements based on their atomic number, properties and electronic configuration. The table is arranged into groups and periods. The elements which are metallic in nature, occupy the large lower-left portion of the table. The non-metals occupy the small upper-right portion of the table. Metalloids like along the staircase line. Elements which appear in the same group have similar behaviour.
(d)
Interpretation:
The coloured boxes that represent three elements that are solid at room temperature are to be identified.
Concept introduction:
A periodic table is an arrangement of elements based on their atomic number, properties and electronic configuration. The table is arranged into groups and periods. The elements which are metallic in nature, occupy the large lower-left portion of the table. The non-metals occupy the small upper-right portion of the table. Metalloids like along the staircase line. Elements which appear in the same group have similar behaviour.
(e)
Interpretation:
A pair of elements that will form a covalent compound is to be determined.
Concept introduction:
Covalent compounds are formed by the interaction of two or more non-metal elements. In covalent compounds, the covalent bonds are formed by the sharing of electrons between the atoms instead of their transfer from one atom to another.
(f)
Interpretation:
Another pair of elements that will likely form covalent compounds is to be determined.
Concept introduction:
Covalent compounds are formed by the interaction of two or more non-metal elements. In covalent compounds, the covalent bonds are formed by the sharing of electrons between the atoms instead of their transfer from one atom to another.
(g)
Interpretation:
The coloured boxes that represent a pair of elements that will likely form an ionic compound with the formula
Concept introduction:
Ionic compounds are formed by the interaction of metal elements with non-metal elements. In an ionic bond formation, there is a transfer of electrons between atoms. The metal elements have a tendency to lose electrons in order to gain stability, whereas non-metals acquire stability by gaining the electrons. The ions thus formed attract each other due to strong electrostatic force between them to form ionic compounds.
(h)
Interpretation:
The coloured boxes that represent another pair of elements that will likely form an ionic compound with the formula
Concept introduction:
Ionic compounds are formed by the interaction of metal elements with non-metal elements. In an ionic bond formation, there is a transfer of electrons between atoms. The metal elements have a tendency to lose electrons in order to gain stability, whereas non-metals acquire stability by gaining the electrons. The ions thus formed attract each other due to strong electrostatic force between them to form ionic compounds.
(i)
Interpretation:
The coloured boxes that represent a pair of elements that will likely form an ionic compound with the formula
Concept introduction:
Ionic compounds are formed by the interaction of metal elements with non-metal elements. In an ionic bond formation, there is a transfer of electrons between atoms. The metal elements have a tendency to lose electrons in order to gain stability, whereas non-metals acquire stability by gaining the electrons. The ions thus formed attract each other due to strong electrostatic force between them to form ionic compounds.
(j)
Interpretation:
The coloured boxes that represent a pair of elements that will likely form an ionic compound with the formula
Concept introduction:
Ionic compounds are formed by the interaction of metal elements with non-metal elements. In an ionic bond formation, there is a transfer of electrons between atoms. The metal elements have a tendency to lose electrons in order to gain stability, whereas non-metals acquire stability by gaining the electrons. The ions thus formed attract each other due to strong electrostatic force between them to form ionic compounds.
(k)
Interpretation:
The coloured box that represents an element that forms no compound is to be determined.
Concept introduction:
A periodic table is an arrangement of elements based on their atomic number, properties and electronic configuration. The table is arranged into groups and periods. The elements which are metallic in nature, occupy the large lower-left portion of the table. The non-metals occupy the small upper-right portion of the table. Metalloids like along the staircase line. Elements which appear in the same group have similar behaviour.
(l)
Interpretation:
The coloured boxes that represent a pair of elements whose compounds exhibit the law of multiple proportions are to be determined.
Concept introduction:
Law of multiple proportions states that, if two elements can combine to form more than one compound, the masses of one element that combines with a fixed mass of the other element are in the ratio of small whole numbers.
![Check Mark](/static/check-mark.png)
Trending nowThis is a popular solution!
![Blurred answer](/static/blurred-answer.jpg)
Chapter 2 Solutions
CHEMISTRY:MOLECULAR...V.2 W/ACCESS
- 46. Consider an ideal gas that occupies 2.50 dm³ at a pressure of 3.00 bar. If the gas is compressed isothermally at a constant external pressure so that the final volume is 0.500 dm³, calculate the smallest value Rest can have. Calculate the work involved using this value of Rext.arrow_forwardNonearrow_forward2010. Suppose that a 10 kg mass of iron at 20 C is dropped from a heigh of 100 meters. What is the kinetics energy of the mass just before it hits the ground, assuming no air resistance? What is its speed? What would be the final temperature of the mass if all the kinetic energy at impact is transformed into internal energy? The molar heat capacity of iron is Cpp = 25.1J mol-¹ K-1 and the gravitational acceleration constant is 9.8 m s¯² |arrow_forward
- ell last during 7. Write the isotopes and their % abundance of isotopes of i) Cl ii) Br 8. Circle all the molecules that show Molecular ion peak as an odd number? c) NH2CH2CH2NH2 d) C6H5NH2 a) CH³CN b) CH3OHarrow_forwardCalsulate specific heat Dissolution of NaOH ก ง ง Mass of water in cup Final temp. of water + NaOH Initial temp. of water AT Water AH Dissolution NaOH - "CaicuraORT. AH (NaOH)=-AH( 30g (water) 29.0°C 210°C 8°C (82) 100 3.. =1003.20 Conjosarrow_forwardPlease provide throrough analysis to apply into further problems.arrow_forward
- Molecular ion peak: the peak corresponding to the intact morecure (with a positive charge) 4. What would the base peak and Molecular ion peaks when isobutane is subjected to Mass spectrometry? Draw the structures and write the molecular weights of the fragments. 5. Circle most stable cation a) tert-butyl cation b) Isopropyl cation c) Ethyl cation. d)Methyl cationarrow_forwardHow many arrangements are there of 15 indistinguishable lattice gas particles distributed on: a.V = 15 sites b.V = 16 sites c.V = 20 sitesarrow_forwardFor which element is the 3d subshell higher in energy than that 4s subshell? Group of answer choices Zr Ca V Niarrow_forward
- ii) Molecular ion peak :the peak corresponding to the intact molecule (with a positive charge) What would the base peak and Molecular ion peaks when isobutane is subjected to Mass spectrometry? Draw the structures and write the molecular weights of the fragments. Circle most stable cation a) tert-butyl cation b) Isopropyl cation c) Ethyl cation. d) Methyl cation 6. What does a loss of 15 represent in Mass spectrum? a fragment of the molecule with a mass of 15 atomic mass units has been lost during the ionization Process 7. Write the isotopes and their % abundance of isotopes of i) Clarrow_forwardChoose a number and match the atomic number to your element on the periodic table. For your element, write each of these features on a side of your figure. 1. Element Name and symbol 2. Family and group 3. What is it used for? 4. Sketch the Valence electron orbital 5. What ions formed. What is it's block on the periodic table. 6. Common compounds 7. Atomic number 8. Mass number 9. Number of neutrons- (show calculations) 10. Sketch the spectral display of the element 11.Properties 12. Electron configuration 13. Submit a video of a 3-meter toss in slow-moarrow_forward[In this question, there are multiple answers to type in a "fill-in-the-blank" fashion - in each case, type in a whole number.] Consider using Slater's Rules to calculate the shielding factor (S) for the last electron in silicon (Si). There will be electrons with a 0.35 S-multiplier, electrons with a 0.85 S-multiplier, and electrons with a 1.00 S-multiplier.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)