Concept explainers
Interpretation:
The
Concept introduction:
An

Answer to Problem 2.11P
(A) The names of the functional groups from the given table that possess at least one
(B) The names of the functional groups from the given table which possess at least one
(C) The functional groups from the given table which possess no H-bond donors and no
Explanation of Solution
(A) The functional groups from the given table which possess at least one
- The given functional group is Nitrile:
In this functional group, due to the high electronegativity of the N atom with a lone pair of electrons, there is one H-bond acceptor.
2) The given functional group is Ether:
In this functional group, due to the high electronegativity of the O atom with a lone pair of electrons, there is one H-bond acceptor.
3) The given functional group is Ketone:
In this functional group, due to the high electronegativity of the O atom with a lone pair of electrons, there is one H-bond acceptor.
4) The given functional group is Acetal:
In this functional group, due to the high electronegativity of the O atom with a lone pair of electrons, there are two H-bond acceptors.
- The given functional group is Aldehyde:
In this functional group, due to the high electronegativity of the O atom with a lone pair of electrons, there is one H-bond acceptor.
- The given functional group is Alkyl halide (Only if X = F):
In this functional group, due to the high electronegativity of the F atom with a lone pair of electrons, there is one H-bond acceptor.
- The given functional group is Epoxide:
In this functional group, due to the high electronegativity of the O atom with a lone pair of electrons, there is one H-bond acceptor.
- The given functional group is Ester:
In this functional group, due to the high electronegativity of the O atoms with a lone pair of electrons, there are two H-bond acceptors.
- The given functional group is Amine:
In this functional group, due to the high electronegativity of the N atom with a lone pair of electrons, there is one H-bond acceptor.
- The given functional group is Amide:
In this functional group, due to the high electronegativity of the N atom with a lone pair of electrons, there is one H-bond acceptor.
(B) The functional groups possessing at least one H-bond donor and one H-bond acceptor are:
1) The given functional group is Hemiacetal:
In this functional group, there is one H-bond donor and two H-bond acceptors. The high electronegativity of the O atom ensures that the O-H bond is highly polar and gives the H atom a large partial positive charge. This sets up a strong attraction between the H atom and the oppositely charged acceptor.
2) The given functional group is Carboxylic acid:
In this functional group, there is one H-bond donor and two H-bond acceptors. The high electronegativity of the O atom ensures that the O-H bond is highly polar and gives the H atom a large partial positive charge. This sets up a strong attraction between the H atom and the oppositely charged acceptor.
- The given functional group is Alcohol:
In this functional group, there is one H-bond donor and one H-bond acceptor. The high electronegativity of the O atom ensures that the O-H bond is highly polar and gives the H atom a large partial positive charge. This sets up a strong attraction between the H atom and the oppositely charged acceptor.
4) The given functional group is Phenol:
In this functional group, there is one H-bond donor and one H-bond acceptor. The high electronegativity of the O atom ensures that the O-H bond is highly polar and gives the H atom a large partial positive charge. This sets up a strong attraction between the H atom and the oppositely charged acceptor.
(C) The functional groups from the given table which possess no H-bond donor and no H-bond acceptor are:
1) The given functional group is Alkene:
In this functional group, there is no H atom which is covalently bonded to a strongly electronegative atom such as N, O, or F. Therefore, there is no H-bond donor and H-bond acceptor.
2) The given functional group is Thiol:
In this functional group, there is no H atom which is covalently bonded to a strongly electronegative atom such as N, O, or F. Therefore, there is no H-bond donor and H-bond acceptor.
3) The given functional group is Alkyne:
In this functional group, there is no H atom which is covalently bonded to a strongly electronegative atom such as N, O, or F. Therefore, there is no H-bond donor and H-bond acceptor.
- The given functional group is Arene or aromatic compound:
In this functional group, there is no H atom which is covalently bonded to a strongly electronegative atom such as N, O, or F. Therefore, there is no H-bond donor and H-bond acceptor.
- The given functional group is Alkyl halide (Only if X = Cl, Br, I):
In this functional group, there is no H atom which is covalently bonded to a strongly electronegative atom such as N, O, or F. Therefore, there is no H-bond donor and H-bond acceptor.
The H-bond donor and H-bond acceptor of the given compounds are predicted on the basis of the number of electronegative atoms that are covalently bonded with hydrogen atoms and with a large concentration of negative charge and lone pair of electrons.
Want to see more full solutions like this?
Chapter 2 Solutions
Organic Chemistry: Principles And Mechanisms
- curved arrows are used to illustrate the flow of electrons. using the provided starting and product structures, draw the cured electron-pushing arrows for thw following reaction or mechanistic steps. be sure to account for all bond-breaking and bond making stepsarrow_forwardUsing the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.arrow_forwardSynthesis of Dibenzalacetone [References] Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below. Question 1 1 pt Question 2 1 pt Question 3 1 pt H Question 4 1 pt Question 5 1 pt Question 6 1 pt Question 7 1pt Question 8 1 pt Progress: 7/8 items Que Feb 24 at You do not have to consider stereochemistry. . Draw the enolate ion in its carbanion form. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. ⚫ Separate multiple reactants using the + sign from the drop-down menu. ? 4arrow_forward
- Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)arrow_forwardHi I need help on the question provided in the image.arrow_forwardDraw a reasonable mechanism for the following reaction:arrow_forward
- Draw the mechanism for the following reaction: CH3 CH3 Et-OH Et Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. H± EXP. L CONT. י Α [1] осн CH3 а CH3 :Ö Et H 0 N о S 0 Br Et-ÖH | P LL Farrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCl. What is the molarity of the HCl?arrow_forward20.00 mL of 0.025 M HCl is titrated with 0.035 M KOH. What volume of KOH is needed?arrow_forward
- 20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCl. What is the molarity of the HCl?arrow_forward20.00 mL of 0.025 M HCl is titrated with 0.035 M KOH. What volume of KOH is needed?arrow_forward20.00 mL of 0.150 M HCl is titrated with 37.75 mL of NaOH. What is the molarity of the NaOH?arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
