
Concept explainers
The following tables show the first-round winning scores of the NCAA men's and women's basketball teams.
TABLE 2-17 Men's Winning First-Round NCAA Tournament Scores
95 | 70 | 79 | 99 | 83 | 72 | 79 | 101 |
69 | 82 | 86 | 70 | 79 | 69 | 69 | 70 |
95 | 70 | 77 | 61 | 69 | 68 | 69 | 72 |
89 | 66 | 84 | 77 | 50 | 83 | 63 | 58 |
TABLE 2-18 Women's Winning First-Round NCAA Tournament Scores
80 | 68 | 51 | 80 | 83 | 75 | 77 | 100 |
96 | 68 | 89 | 80 | 67 | 84 | 76 | 70 |
98 | 81 | 79 | 89 | 98 | 83 | 72 | 100 |
101 | 83 | 66 | 76 | 77 | 84 | 71 | 77 |
Use the software or method of your choice to construct separate histograms for the men's and women's winning scores Try 5, 7, and 10 classes for each. Which number of classes seems to be the best choice? Why?

To graph: The histogram for men’s and women’s winning score data..
Explanation of Solution
Calculation: For Men’s winning score data:
The largest value of the data set is 101 and the smallest value is 50 in the men’s winning score data.
Using five classes, the class width is calculated in the following way:
The frequency table is as follows:
Class-limits | Class boundaries | Frequency |
50–60 | 49.5–60.5 | 2 |
61–71 | 60.5–71.5 | 13 |
72–82 | 71.5–82.5 | 8 |
83–93 | 82.5–93.5 | 5 |
94–104 | 93.5–104.5 | 4 |
To construct the histogram by using the MINITAB, the steps are as follows:
Step 1: Enter the class boundaries in C1 and frequency in C2.
Step 2: Go to Graph > Histogram > Simple.
Step 3: Enter C1 in Graph variable, then go to Data options > Frequency > C2.
Step 4: Click on OK.
The obtained histogram is
Using seven classes, the class width is calculated in the following way:
Class-limits | Class boundaries | Frequency |
50–57 | 49.5–57.5 | 1 |
58–65 | 57.5–65.5 | 3 |
66–73 | 65.5–73.5 | 13 |
74–81 | 73.5–81.5 | 5 |
82–89 | 81.5–89.5 | 6 |
90–97 | 89.5–97.5 | 2 |
98–105 | 97.5–10.5 | 2 |
To construct the histogram by using the MINITAB, the steps are as follows:
Step 1: Enter the class boundaries in C3 and frequency in C4.
Step 2: Go to Graph > Histogram > Simple.
Step 3: Enter C3 in Graph variable, then go to Data options > Frequency > C4.
Step 4: Click on OK.
The obtained histogram is
Using 10 classes, the class width is calculated in the following way:
Class-limits | Class boundaries | Frequency |
50–55 | 49.5–55.5 | 1 |
56–61 | 55.5–61.5 | 2 |
62–67 | 61.5–67.5 | 2 |
68–73 | 67.5–73.5 | 12 |
74–79 | 73.5–79.5 | 5 |
80–85 | 79.5–85.5 | 4 |
86–91 | 85.5–91.5 | 2 |
92–97 | 91.5–97.5 | 2 |
98–103 | 97.5–103.5 | 2 |
104–109 | 103.5–109.5 | 0 |
To construct the histogram by using the MINITAB, the steps are as follows:
Step 1: Enter the class boundaries in C5 and frequency in C6.
Step 2: Go to Graph > Histogram > Simple.
Step 3: Enter C5 in Graph variable, then go to Data options > Frequency > C6.
Step 4: Click on OK.
The obtained histogram is
For Women’s winning score data:
The largest value of the data set is 101 and the smallest value is 51 in the women’s winning score data.
Using five classes, the class width calculated in the following way:
The frequency table is as follows:
Class-limits | Class boundaries | Frequency |
51–61 | 50.5–61.5 | 1 |
62–72 | 61.5–72.5 | 7 |
73–83 | 72.5–83.5 | 14 |
84–94 | 83.5–94.5 | 4 |
95–105 | 94.5–105.5 | 6 |
To construct the histogram by using the MINITAB, the steps are as follows:
Step 1: Enter the class boundaries in C7 and frequency in C8.
Step 2: Go to Graph > Histogram > Simple.
Step 3: Enter C8 in Graph variable, then go to Data options > Frequency > C8.
Step 4: Click on OK.
The obtained histogram is
Using seven classes, the class width is calculated in the following way:
The frequency table is as follows:
Class-limits | Class boundaries | Frequency |
51–58 | 51.5–58.5 | 1 |
59–66 | 58.5–66.5 | 1 |
67–74 | 66.5–74.5 | 6 |
75–82 | 74.5–82.5 | 11 |
83–90 | 82.5–90.5 | 7 |
91–98 | 90.5–98.5 | 3 |
99–106 | 98.5–106.5 | 3 |
To construct the histogram by using the MINITAB, the steps are as follows:
Step 1: Enter the class boundaries in C9 and frequency in C10.
Step 2: Go to Graph > Histogram > Simple.
Step 3: Enter C9 in Graph variable, then go to Data options > Frequency > C10.
Step 4: Click on OK.
The obtained histogram is:
Using 10 classes, the class width calculated in the following way:
The frequency table is as follows:
Class-limits | Class boundaries | Frequency |
51–55 | 50.5–55.5 | 1 |
56–60 | 55.5–60.5 | 0 |
61–65 | 60.5–65.5 | 0 |
66–70 | 65.5–70.5 | 5 |
71–75 | 70.5–75.5 | 3 |
76–80 | 75.5–80.5 | 9 |
81–85 | 80.5–85.5 | 6 |
86–90 | 85.5–90.5 | 2 |
91–95 | 90.5–95.5 | 0 |
96 and more | 95.5 and more | 6 |
To construct the histogram by using the MINITAB, the steps are as follows:
Step 1: Enter the class boundaries in C11 and frequency in C12.
Step 2: Go to Graph > Histogram > Simple.
Step 3: Enter C11 in Graph variable, then go to Data options > Frequency > C12.
Step 4: Click on OK.
The obtained histogram is
Using number classes five and seven in both data sets of men’s and women’s seem to be the best because histograms for that classes shows reliable distribution but using classes ten show gap between the bars. Since, using five classes seems best than using classes seven.
Want to see more full solutions like this?
Chapter 2 Solutions
Understanding Basic Statistics
- A marketing agency wants to determine whether different advertising platforms generate significantly different levels of customer engagement. The agency measures the average number of daily clicks on ads for three platforms: Social Media, Search Engines, and Email Campaigns. The agency collects data on daily clicks for each platform over a 10-day period and wants to test whether there is a statistically significant difference in the mean number of daily clicks among these platforms. Conduct ANOVA test. You can provide your answer by inserting a text box and the answer must include: also please provide a step by on getting the answers in excel Null hypothesis, Alternative hypothesis, Show answer (output table/summary table), and Conclusion based on the P value.arrow_forwardA company found that the daily sales revenue of its flagship product follows a normal distribution with a mean of $4500 and a standard deviation of $450. The company defines a "high-sales day" that is, any day with sales exceeding $4800. please provide a step by step on how to get the answers Q: What percentage of days can the company expect to have "high-sales days" or sales greater than $4800? Q: What is the sales revenue threshold for the bottom 10% of days? (please note that 10% refers to the probability/area under bell curve towards the lower tail of bell curve) Provide answers in the yellow cellsarrow_forwardBusiness Discussarrow_forward
- The following data represent total ventilation measured in liters of air per minute per square meter of body area for two independent (and randomly chosen) samples. Analyze these data using the appropriate non-parametric hypothesis testarrow_forwardeach column represents before & after measurements on the same individual. Analyze with the appropriate non-parametric hypothesis test for a paired design.arrow_forwardShould you be confident in applying your regression equation to estimate the heart rate of a python at 35°C? Why or why not?arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL

