
Concept explainers
The number of neutrons in the nucleus is the atomic number of that element.

Whether the given statement is true or false.
Answer to Problem 1TFQ
False.
Explanation of Solution
Given:
The given statement is:
An atomic number of an element is the count of neutrons in the nucleus of that element.
Calculation:
The atomic number of an element can be defined as the number of protons in an atom. The atomic weight or also called as the mass number of an element is equal to the number of protons and neutrons in an atom.
That is,
Atomic weight = Number of neutrons + Number of protons
Atomic weight = Number of neutrons + Atomic number
Number of neutrons = Atomic weight - Atomic number
Therefore, the atomic number of an element is not equal to the count of neutrons in the nucleus of that element.
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Chapter 2 Solutions
Electronics Fundamentals: Circuits, Devices & Applications
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- b) The joint probability function for the random variables X and Y is given in Table below. Find a) the marginal probability function of X and Y. P(Y/X) and P(X/Y). c) P(X ≥ 2, Y ≤ 2) y 1 2 3 10.05 0.05 0.1 P(X, Y) = X 20.05 0.1 0.35 3 0 0.2 0.1arrow_forwardSuppose a random variable X as pmf / Px (x) = { %, x = 1, 2, 3, 0, otherwise. find constand c ①P(X = 1), P(X 7,2), PC1 3) C CDFarrow_forwardSuppose that a coin is tossed three so that the sample space is Let X represent the number of heads that can come up. i) Find the probability function corresponding to the random variable X. Assuming that the coin is fair ii) Find the distribution function for the random variable X. iii) Obtain its graph.arrow_forward
- Q9 A single-phase transformer, 2500 / 250 V, 50 kVA, 50 Hz has the following parameters, the Primary and secondary resistances are 0.8 ohm and 0.012 ohm respectively, the primary and secondary reactance are 4 ohm and 0.04 ohm respectively and the transformer gives 96% maximum efficiency at 75% full-load. The magnetizing component of-load current is 1.2 A on 2500 V side. 1- Draw the equivalent circuit referred to primary (H.V side) and inserts all the values in it 2- Find out Ammeter, voltmeter and wattmeter readings on open-circuit and short-circuit test. If supply is given to 2500 V side in both cases. Ans. O.C. Test (Vo= 2500 V, lo=1.24 A, Wo=781.25 w) S.C. Test (Vsc =164.924 V, Isc =20 A, Wsc =800 w )arrow_forwardQ2-A)- Enumerate the various losses in transformer. Explain how each loss varies with (Load current, supply voltage). B)- Draw the pharos diagram at load on primary side.arrow_forwardQ2- What are the parameters and loss that can be determined during open-circuit test of singlephase transformer. Draw the circuit diagram of open-circuit test and explain how can you calculate the Parameters and loss.arrow_forward
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage LearningDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning

