A person gets in an elevator on the ground floor and rides it to the top floor of a building. Sketch a velocity-versus-time graph for this motion.

Question

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Answer 1

Textbook Question

Chapter 2, Problem 1CQ

A person gets in an elevator on the ground floor and rides it to the top floor of a building. Sketch a velocity-versus-time graph for this motion.

Expert Solution & Answer

To determine

To draw: The velocity-versus-time graph.

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.

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01:03

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Answer 2

Textbook Question

Chapter 2, Problem 1CQ

A person gets in an elevator on the ground floor and rides it to the top floor of a building. Sketch a velocity-versus-time graph for this motion.

Expert Solution & Answer

To determine

To draw: The velocity-versus-time graph.

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:03

Answer 3

Textbook Question

Chapter 2, Problem 1CQ

A person gets in an elevator on the ground floor and rides it to the top floor of a building. Sketch a velocity-versus-time graph for this motion.

Expert Solution & Answer

To determine

To draw: The velocity-versus-time graph.

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:03

Answer 4

Textbook Question

Chapter 2, Problem 1CQ

A person gets in an elevator on the ground floor and rides it to the top floor of a building. Sketch a velocity-versus-time graph for this motion.

Expert Solution & Answer

To determine

To draw: The velocity-versus-time graph.

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:03

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

To draw: The velocity-versus-time graph.

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.

Answer 8

Expert Solution & Answer

To determine

To draw: The velocity-versus-time graph.

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

To draw: The velocity-versus-time graph.

Answer 12

Answer to Problem 1CQ

The velocity-versus-time graph is drawn.

Answer 13

Explanation of Solution

Given data:

A person gets in an elevator on the ground floor and rides it to the top floor of a building.

Explanation:

Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.

The velocity-versus-time graph for the above scenario is shown in Figure 1.

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+), Chapter 2, Problem 1CQ

Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.

Conclusion:

Hence, the velocity-versus-time graph is drawn.