Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
9th Edition
ISBN: 9781319055967
Author: Moore
Publisher: MAC HIGHER
bartleby

Videos

Question
Book Icon
Chapter 2, Problem 153E

(a)

To determine

To find: The marginal total of the provided data to add them in the table.

(a)

Expert Solution
Check Mark

Answer to Problem 153E

Solution: The obtained marginal totals are shown in the below table.

Field of study

Canada

France

Germany

Italy

Japan

UK

US

Total`

SsBL

64

153

66

125

250

152

878

1688

SME

35

111

66

80

136

128

355

911

AH

27

74

33

42

123

105

397

801

Ed

20

45

18

16

39

14

167

319

Other

30

289

35

58

97

76

272

857

Total

176

672

218

321

645

475

2069

4576

Explanation of Solution

Calculation: To obtain the marginal totals, below steps are followed in the Minitab software.

Step 1: Enter the data in Minitab worksheet.

Step 2: Go to Stat > Tables > Descriptive Statistics.

Step 3: Select “Field” in “For rows” and select “Country” in “For columns”. And select “Count” in “Frequencies are in”.

Step 4: Select the option “Counts” under the “Categorical Variables”.

Step 5: Click OK twice.

The totals are obtained as the Minitab output. The obtained marginal totals are shown in the below table.

Field of study

Canada

France

Germany

Italy

Japan

UK

US

Total

SsBL

64

153

66

125

250

152

878

1688

SME

35

111

66

80

136

128

355

911

AH

27

74

33

42

123

105

397

801

Ed

20

45

18

16

39

14

167

319

Other

30

289

35

58

97

76

272

857

Total

176

672

218

321

645

475

2069

4576

Interpretation: The row Total of the table indicates the marginal total corresponding to the Field of Study and the column Total shows the marginal totals for each country.

(b)

To determine

To find: The marginal distribution for the countries of the provided data and the graphical representation of the distribution.

(b)

Expert Solution
Check Mark

Answer to Problem 153E

Solution: The obtained marginal totals are shown in the below table.

Country

Canada

France

Germany

Italy

Japan

UK

US

Total

Marginal Percentage

3.846

14.685

4.764

7.015

14.095

10.38

45.214

100

And the graphical representation is shown below:

Introduction to the Practice of Statistics, Chapter 2, Problem 153E , additional homework tip  1

Explanation of Solution

Calculation: To obtain the marginal distribution, below steps are followed in the Minitab software.

Step 1: Enter the data in Minitab worksheet.

Step 2: Go to Stat > Tables > Descriptive Statistics.

Step 3: Select “Field” in “For rows” and select “Country” in “For columns”. And select “Count” in “Frequencies are in”.

Step 4: Select the option “Total percents” and under the “Categorical Variables”.

Step 5: Click OK twice.

The percentage of totals are obtained as the Minitab output. The obtained marginal distribution are shown in the below table.

Country

Canada

France

Germany

Italy

Japan

UK

US

Total

Marginal Percentage

3.846

14.685

4.764

7.015

14.095

10.38

45.214

100

Graph: The marginal distribution is graphically shown by using the bar graph. To obtained the graphical representation, below steps are followed in the Minitab software.

Step 1: Insert the data into the worksheet.

Step 2: Go to Graph Bar Chart.

Step 3: Click on the drop down menu of “Bar represents” and select “Values from table”.

Step 3: Select “Simple” and click “OK”.

Step 4: Specify the “Graph variables” and “Categorical variable”.

Step 5: Click “OK”.

The bar graph is obtained as:

Introduction to the Practice of Statistics, Chapter 2, Problem 153E , additional homework tip  2

Interpretation: The maximum percentage of students belongs to US whereas the minimum percentage of the students belongs to Canada.

(c)

To determine

To find: The marginal distribution for the Field of study of the provided data and the graphical representation of the distribution.

(c)

Expert Solution
Check Mark

Answer to Problem 153E

Solution: The obtained marginal totals are shown in the below table.

Field of study

SsBL

SME

AH

Ed

Other

Total

Marginal Percentage

36.888

19.908

17.504

6.971

18.728

100

And the graphical representation is shown below:

Introduction to the Practice of Statistics, Chapter 2, Problem 153E , additional homework tip  3

Explanation of Solution

Calculation: To obtained the marginal totals, below steps are followed in the Minitab software.

Step 1: Enter the data in Minitab worksheet.

Step 2: Go to Stat > Tables > Descriptive Statistics.

Step 3: Select “Field” in “For rows” and select “Country” in “For columns”. And select “Count” in “Frequencies are in”.

Step 4: Select the option “Total percents” and under the “Categorical Variables”.

Step 5: Click OK twice.

The percentage of totals are obtained as the Minitab output. The obtained marginal distribution are shown in the below table.

Field of study

SsBL

SME

AH

Ed

Other

Total

Marginal Percentage

17.504

6.971

18.728

19.908

36.888

100

Graph: The marginal distribution is graphically shown by using the bar graph. To obtain the graphical representation, below steps are followed in the Minitab software.

Step 1: Insert the data into the worksheet.

Step 2: Go to Graph Bar Chart.

Step 3: Click on the drop down menu of “Bar represents” and select “Values from table”.

Step 3: Select “Simple” and click “OK”.

Step 4: Specify the “Graph variables” and “Categorical variable”.

Step 5: Click “OK”.

The bar graph is obtained as:

Introduction to the Practice of Statistics, Chapter 2, Problem 153E , additional homework tip  4

Interpretation: The maximum percentage of students studies SsBL fields whereas the minimum percentage of the students studies Ed.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Microsoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADO
Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined. 1.What percent of the refunds are more than $3,500? 2. What percent of the refunds are more than $3500 but less than $3579? 3. What percent of the refunds are more than $3325 but less than $3579?
A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…

Chapter 2 Solutions

Introduction to the Practice of Statistics

Ch. 2.2 - Prob. 11UYKCh. 2.2 - Prob. 12UYKCh. 2.2 - Prob. 13UYKCh. 2.2 - Prob. 14UYKCh. 2.2 - Prob. 15UYKCh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.2 - Prob. 30ECh. 2.2 - Prob. 31ECh. 2.2 - Prob. 32ECh. 2.2 - Prob. 33ECh. 2.2 - Prob. 34ECh. 2.2 - Prob. 35ECh. 2.2 - Prob. 36ECh. 2.2 - Prob. 37ECh. 2.3 - Prob. 38UYKCh. 2.3 - Prob. 39UYKCh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59ECh. 2.3 - Prob. 60ECh. 2.4 - Prob. 61UYKCh. 2.4 - Prob. 62UYKCh. 2.4 - Prob. 63UYKCh. 2.4 - Prob. 64UYKCh. 2.4 - Prob. 65ECh. 2.4 - Prob. 66ECh. 2.4 - Prob. 67ECh. 2.4 - Prob. 68ECh. 2.4 - Prob. 69ECh. 2.4 - Prob. 70ECh. 2.4 - Prob. 71ECh. 2.4 - Prob. 72ECh. 2.4 - Prob. 73ECh. 2.4 - Prob. 74ECh. 2.4 - Prob. 75ECh. 2.4 - Prob. 76ECh. 2.4 - Prob. 77ECh. 2.4 - Prob. 78ECh. 2.4 - Prob. 79ECh. 2.4 - Prob. 80ECh. 2.4 - Prob. 81ECh. 2.4 - Prob. 82ECh. 2.4 - Prob. 83ECh. 2.4 - Prob. 84ECh. 2.4 - Prob. 85ECh. 2.4 - Prob. 86ECh. 2.4 - Prob. 87ECh. 2.4 - Prob. 88ECh. 2.4 - Prob. 89ECh. 2.4 - Prob. 90ECh. 2.4 - Prob. 91ECh. 2.5 - Prob. 92UYKCh. 2.5 - Prob. 93UYKCh. 2.5 - Prob. 94ECh. 2.5 - Prob. 95ECh. 2.5 - Prob. 96ECh. 2.5 - Prob. 97ECh. 2.5 - Prob. 98ECh. 2.5 - Prob. 99ECh. 2.5 - Prob. 100ECh. 2.5 - Prob. 101ECh. 2.5 - Prob. 102ECh. 2.5 - Prob. 103ECh. 2.5 - Prob. 104ECh. 2.5 - Prob. 105ECh. 2.5 - Prob. 106ECh. 2.5 - Prob. 107ECh. 2.5 - Prob. 108ECh. 2.5 - Prob. 110ECh. 2.5 - Prob. 111ECh. 2.5 - Prob. 112ECh. 2.6 - Prob. 113UYKCh. 2.6 - Prob. 114UYKCh. 2.6 - Prob. 115UYKCh. 2.6 - Prob. 116UYKCh. 2.6 - Prob. 117UYKCh. 2.6 - Prob. 118UYKCh. 2.6 - Prob. 119ECh. 2.6 - Prob. 120ECh. 2.6 - Prob. 121ECh. 2.6 - Prob. 122ECh. 2.6 - Prob. 123ECh. 2.6 - Prob. 124ECh. 2.6 - Prob. 125ECh. 2.6 - Prob. 126ECh. 2.6 - Prob. 127ECh. 2.6 - Prob. 128ECh. 2.6 - Prob. 129ECh. 2.6 - Prob. 130ECh. 2.7 - Prob. 131ECh. 2.7 - Prob. 132ECh. 2.7 - Prob. 133ECh. 2.7 - Prob. 134ECh. 2.7 - Prob. 135ECh. 2.7 - Prob. 136ECh. 2.7 - Prob. 137ECh. 2.7 - Prob. 138ECh. 2.7 - Prob. 139ECh. 2.7 - Prob. 140ECh. 2.7 - Prob. 141ECh. 2.7 - Prob. 142ECh. 2.7 - Prob. 143ECh. 2 - Prob. 144ECh. 2 - Prob. 145ECh. 2 - Prob. 146ECh. 2 - Prob. 147ECh. 2 - Prob. 148ECh. 2 - Prob. 149ECh. 2 - Prob. 150ECh. 2 - Prob. 151ECh. 2 - Prob. 152ECh. 2 - Prob. 153ECh. 2 - Prob. 154ECh. 2 - Prob. 155ECh. 2 - Prob. 156ECh. 2 - Prob. 157ECh. 2 - Prob. 158ECh. 2 - Prob. 159ECh. 2 - Prob. 160ECh. 2 - Prob. 161ECh. 2 - Prob. 162ECh. 2 - Prob. 163ECh. 2 - Prob. 164ECh. 2 - Prob. 165ECh. 2 - Prob. 166ECh. 2 - Prob. 167ECh. 2 - Prob. 168ECh. 2 - Prob. 169ECh. 2 - Prob. 170ECh. 2 - Prob. 171ECh. 2 - Prob. 172ECh. 2 - Prob. 173ECh. 2 - Prob. 174ECh. 2 - Prob. 175ECh. 2 - Prob. 176E
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Text book image
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Text book image
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Text book image
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
Text book image
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Text book image
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman
Hypothesis Testing using Confidence Interval Approach; Author: BUM2413 Applied Statistics UMP;https://www.youtube.com/watch?v=Hq1l3e9pLyY;License: Standard YouTube License, CC-BY
Hypothesis Testing - Difference of Two Means - Student's -Distribution & Normal Distribution; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=UcZwyzwWU7o;License: Standard Youtube License