Concept explainers
(a)
To graph: The
(a)
Explanation of Solution
Graph: To draw the scatterplot for the provided data set, the below steps are followed in Minitab software.
Step 1: Open the “MEIS” file in Minitab software.
Step 2: Go to Graph
Step 3: Choose the option “Simple” and click “OK”.
Step 4: Select “Sales” as Y variables and “Dwellpermit” as X variables.
Step 5: Click “OK” twice.
The scatterplot is obtained as:
To explain: The relationship between the variables and the presence of the outliers.
Answer to Problem 144E
Solution: Though the relationship between the variables is very weak, but there is no outlier in the data set.
Explanation of Solution
(b)
To find: The least-squares regression line for the data.
(b)
Answer to Problem 144E
Solution: The least-squares regression line is obtained as
Explanation of Solution
Calculation: To draw the regression line and obtain the sketch of the regression line, the below steps are followed in the Minitab software.
Step 1: Right click on the obtained graph in the part (a).
Step 2: Go to Add
Step 3: Click on “Linear” under the menu “Model Order” and tick the “Fit intercept”.
Step 4: Click on “OK” to obtain the regression line.
The obtained regression equation is
Graph: The below graph shows the regression line.
(c)
To explain: The slope of the obtained line.
(c)
Answer to Problem 144E
Solution: The slope can be interpreted as if there is an increase of 1unit of the variable, issued permit for dwelling then there is an increase of 0.1263 units in the value of the variable sales.
Explanation of Solution
(d)
To explain: The intercept of the line.
(d)
Answer to Problem 144E
Solution: The intercept can be interpreted as the value of the response variable when the value of the explanatory variable is zero. As the value of the response variable is 109.8 for the zero issued permits, it is appropriate to use the intercept for explaining the relationship between the variables.
Explanation of Solution
(e)
The sales for an index of 224 dwelling permits.
(e)
Answer to Problem 144E
Solution: The predicted value of the sales is 138.0912.
Explanation of Solution
The predicted value can be calculated as:
(f)
To find: The residual value for Canada.
(f)
Answer to Problem 144E
Solution: The obtained value of the residual is
Explanation of Solution
Calculation: The sale for the Canada is provided as 122. The residual value for the sales for Canada whose index of dwelling permits is 224 is calculated as:
(g)
The percentage of variability in sales is explained by dwelling permit.
(g)
Answer to Problem 144E
Solution: The explained percentage of variability in sales is 10.30%.
Explanation of Solution
Therefore, the proportion of variation that is explained by the explanatory variables of the model is 10.30%.
Want to see more full solutions like this?
Chapter 2 Solutions
Introduction to the Practice of Statistics
- Let X be a random variable with support SX = {−3, 0.5, 3, −2.5, 3.5}. Part ofits probability mass function (PMF) is given bypX(−3) = 0.15, pX(−2.5) = 0.3, pX(3) = 0.2, pX(3.5) = 0.15.(a) Find pX(0.5).(b) Find the cumulative distribution function (CDF), FX(x), of X.1(c) Sketch the graph of FX(x).arrow_forwardA well-known company predominantly makes flat pack furniture for students. Variability with the automated machinery means the wood components are cut with a standard deviation in length of 0.45 mm. After they are cut the components are measured. If their length is more than 1.2 mm from the required length, the components are rejected. a) Calculate the percentage of components that get rejected. b) In a manufacturing run of 1000 units, how many are expected to be rejected? c) The company wishes to install more accurate equipment in order to reduce the rejection rate by one-half, using the same ±1.2mm rejection criterion. Calculate the maximum acceptable standard deviation of the new process.arrow_forward5. Let X and Y be independent random variables and let the superscripts denote symmetrization (recall Sect. 3.6). Show that (X + Y) X+ys.arrow_forward
- 8. Suppose that the moments of the random variable X are constant, that is, suppose that EX" =c for all n ≥ 1, for some constant c. Find the distribution of X.arrow_forward9. The concentration function of a random variable X is defined as Qx(h) = sup P(x ≤ X ≤x+h), h>0. Show that, if X and Y are independent random variables, then Qx+y (h) min{Qx(h). Qr (h)).arrow_forward10. Prove that, if (t)=1+0(12) as asf->> O is a characteristic function, then p = 1.arrow_forward
- 9. The concentration function of a random variable X is defined as Qx(h) sup P(x ≤x≤x+h), h>0. (b) Is it true that Qx(ah) =aQx (h)?arrow_forward3. Let X1, X2,..., X, be independent, Exp(1)-distributed random variables, and set V₁₁ = max Xk and W₁ = X₁+x+x+ Isk≤narrow_forward7. Consider the function (t)=(1+|t|)e, ER. (a) Prove that is a characteristic function. (b) Prove that the corresponding distribution is absolutely continuous. (c) Prove, departing from itself, that the distribution has finite mean and variance. (d) Prove, without computation, that the mean equals 0. (e) Compute the density.arrow_forward
- 1. Show, by using characteristic, or moment generating functions, that if fx(x) = ½ex, -∞0 < x < ∞, then XY₁ - Y2, where Y₁ and Y2 are independent, exponentially distributed random variables.arrow_forward1. Show, by using characteristic, or moment generating functions, that if 1 fx(x): x) = ½exarrow_forward1990) 02-02 50% mesob berceus +7 What's the probability of getting more than 1 head on 10 flips of a fair coin?arrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman