Explanation It is assumed that the solid particles are uniformly distributed throughout the fluid medium. Write the expression for total mass of the mixture m m can be written as m m = m s + m l 1 = m s m m + m l m m ...... (I) Here, The mass of the solid particle is m s and The mass of the liquid particle is m l . Write the expression for concentration of solid. C s , max = m s m m Substitute m s m m the value of C s , max in Equation (I). 1 = m s m m + m l m m 1 = C s,max + m l m m ...... (II) Write the expression for the density of the fluid for solid particle. ρ s = m s V s m s = ρ s V s Here, the density of the solid particle is ρ s and the volume of the solid particle is V s . Write the expression for the density of the fluid for liquid particle. ρ l = m l V l m l = ρ l V l Here, the density of the liquid particle is ρ l and the volume of the liquid particle is V l . Substitute ρ s V s for m s and ρ l V l for m l in Equation (II). 1 = C s , max + ρ l V l ρ m V m ( 1 − C s , max ) = ρ l V l ρ m V m ρ m ρ l = V l V m ( 1 − C s , max ) ...... (III) Write the expression for the volume of the mixture. V m = V s + V l V l V m = 1 − V s V m = 1 − m s / ρ s m m / ρ m

Fluid Mechanics: Fundamentals and Applications

4th Edition

ISBN: 9781259877827

Author: CENGEL

Publisher: MCG

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Chapter 2, Problem 112P

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The specific gravity of water based slurry is 11+Cs,mass(1/SGs−1).

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Chapter 2, Problem 111P

Chapter 2, Problem 113P

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Fluid Mechanics: Fundamentals and Applications

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The specific gravity of water based slurry is 1 1 + C s,mass ( 1 / S G s − 1 ) .

Solution Summary: The author explains the specific gravity of water based slurry. The expression for total mass of the mixture can be written as m_s.

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The specific gravity of water based slurry is 11+Cs,mass(1/SGs−1).

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Chapter 2 Solutions