Database Systems: Design, Implementation, & Management
12th Edition
ISBN: 9781305627482
Author: Carlos Coronel, Steven Morris
Publisher: Cengage Learning
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Chapter 2, Problem 10P
(a)
Explanation of Solution
Tables:
The three tables that are created to describe the relationship between PAINTER, PAINTING, and GALLERY are shown below.
Table Name : “PAINTER”
The following are the components of “PAINTER” table,
| PAINTER NUM | PAINTER FNAME | PAINTER LNAME | PAINTER INITIAL |
| 10014 | Artiste | Josephine | P |
| 10015 | Itero | Julio | G |
| 10016 | McDonald | Theresa |
Table Name: “PAINTING”
The following are the components of “PAINTING” table,
| PAINTING NUM | PAINTING TITLE | PAINTER NUM | GALLERY NUMBER |
| 20018 | Dawn Thunder | 10016 | 18 |
| 20023 | Vanilla Roses | 10015 | 18 |
| 20041 | Tired Flounders | 10016 | 23 | ...
(b)
Explanation of Solution
Relationship between tables:
The relationship between these tables can be described by using a Crow’s Foot ERD.
Crow’s Foot ERD:
Expert Solution & Answer
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 2 Solutions
Database Systems: Design, Implementation, & Management
Ch. 2 - Prob. 1RQCh. 2 - What is a business rule, and what is its purpose...Ch. 2 - How do you translate business rules into data...Ch. 2 - Prob. 4RQCh. 2 - Explain how the entity relationship (ER) model...Ch. 2 - Prob. 6RQCh. 2 - Prob. 7RQCh. 2 - Prob. 8RQCh. 2 - Prob. 9RQCh. 2 - Prob. 10RQ
Ch. 2 - What is a relationship, and what three types of...Ch. 2 - Give an example of each of the three types of...Ch. 2 - What is a table, and what role does it play in the...Ch. 2 - Prob. 14RQCh. 2 - Prob. 15RQCh. 2 - Prob. 16RQCh. 2 - Prob. 17RQCh. 2 - Prob. 18RQCh. 2 - Prob. 19RQCh. 2 - Prob. 20RQCh. 2 - Prob. 21RQCh. 2 - Prob. 22RQCh. 2 - Prob. 23RQCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Using Figure P2.6 as your guide, work Problems 68....Ch. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Typically, a hospital patient receives medications...Ch. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17P
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