Programming with Microsoft Visual Basic 2015 (MindTap Course List)
7th Edition
ISBN: 9781285860268
Author: Diane Zak
Publisher: Cengage Learning
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Chapter 1.LA, Problem 9RQ
Explanation of Solution
Difference between a Form’s Text and Name Property:
| Text property | Name property |
| Text property of the form provides a title for the Form window. | Name property is used to provide a meaningful name for the form or objects used in the project. |
| To see the Text property in the properties window, scroll down the list and click “Text”. | A project may contain many forms; to differentiate the forms from each other, Name property is used. |
| By default, the title of the form is “Form1” in the text property... |
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Specifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named
out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle.Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…
Chapter 1 Solutions
Programming with Microsoft Visual Basic 2015 (MindTap Course List)
Ch. 1.LA - Prob. 1RQCh. 1.LA - Which window is used to set the characteristics...Ch. 1.LA - Prob. 3RQCh. 1.LA - Prob. 4RQCh. 1.LA - Prob. 5RQCh. 1.LA - Prob. 6RQCh. 1.LA - Prob. 7RQCh. 1.LA - Which property determines the initial position of...Ch. 1.LA - Prob. 9RQCh. 1.LA - Prob. 10RQ
Ch. 1.LA - Prob. 11RQCh. 1.LA - Prob. 1ECh. 1.LA - Prob. 2ECh. 1.LA - Prob. 3ECh. 1.LB - Prob. 1RQCh. 1.LB - Prob. 2RQCh. 1.LB - Prob. 3RQCh. 1.LB - Prob. 4RQCh. 1.LB - Prob. 5RQCh. 1.LB - Prob. 1ECh. 1.LB - Prob. 2ECh. 1.LB - Prob. 3ECh. 1.LB - Prob. 4ECh. 1.LC - Prob. 1RQCh. 1.LC - Prob. 2RQCh. 1.LC - Prob. 3RQCh. 1.LC - Prob. 4RQCh. 1.LC - Prob. 5RQCh. 1.LC - Prob. 1ECh. 1.LC - Prob. 2ECh. 1.LC - Prob. 3ECh. 1.LC - Prob. 4ECh. 1.LC - Prob. 5ECh. 1.LC - Prob. 6ECh. 1.LC - Prob. 7ECh. 1.LC - Prob. 8E
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