Chapter 1.FR3, Problem 1E

If $f\left(x\right)=\frac{x+3}{x-1}$, find $f\left(2\right)$.

To determine

To find:

The value of $f\left(2\right)$ for the function $f\left(x\right)=\frac{x+3}{x-1}$.

Answer to Problem 1E

Solution:

The value of $f\left(2\right)$ is $5$.

Explanation of Solution

Approach:

The value of $f\left(a\right)$, if the function $f\left(x\right)$ is given, can be calculated by substituting $a$ for $x$ in that function.

Calculation:

Consider the given function.

$f\left(x\right)=\frac{x+3}{x-1}$

Substitute $2$ for $x$ in above function.

$\begin{array}{rll}f\left(2\right)& =& \frac{2+3}{2-1}\\ & =& \frac{5}{1}\\ & =& 5\end{array}$

Therefore, the value of $f\left(2\right)$ is $5$.