EBK ORGANIC CHEMISTRY AS A SECOND LANGU
EBK ORGANIC CHEMISTRY AS A SECOND LANGU
3rd Edition
ISBN: 9781118203774
Author: Klein
Publisher: YUZU
Question
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Chapter 19.5, Problem 9ATS

(a)

Interpretation Introduction

Interpretation: The reagents and conditions that are required for the given transformation have to be determined.

Concept Introduction:

Acetals:

Acetals are used to protect the ketone and aldehyde (carbonyl group).

In this reaction acetone is protected as acetal by using ethylene glycol. Acetals are less stable compound.

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  1

In acidic condition, an aldehyde or a ketone reacts with two molecules of alcohol or a molecule of diol to form acetal or cyclic acetal respectively.

General scheme:

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  2

Retro synthetic analysis:

It is the analysis of the synthetic starting materials for a given compound through its precursors or fragments which are known as synthons. The synthons can be obtained by logical cleavage of the chemical bonds in the compounds. The resulted synthons will be therefore known as logical synthons.

Retro analysis for acetal formation:

The retro synthetic analysis for any given acetal, enable to find that the starting materials for its formation will be alcohol in case of aliphatic acetal or diol in case of cyclic acetal as well as aldehyde or ketone.

Example:

The retro analysis for a cyclic acetal is shown here:

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  3

The given retro analysis shows that the starting materials for the formation of the acetal are a diol and formaldehyde.

General scheme:

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  4

(b)

Interpretation Introduction

Interpretation: A plausible mechanism for the given reaction has to be drawn.

Concept Introduction:

Acetals:

Acetals are used to protect the ketone and aldehyde (carbonyl group).

In this reaction acetone is protected as acetal by using ethylene glycol. Acetals are less stable compound.

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  5

In acidic condition, an aldehyde or a ketone reacts with two molecules of alcohol or a molecule of diol to form acetal or cyclic acetal respectively.

General scheme:

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  6

(c)

Interpretation Introduction

Interpretation: Based on the given keto-diol precursor, the structure of frontalin has to be drawn.

Concept Introduction:

Acetals:

Acetals are used to protect the ketone and aldehyde (carbonyl group).

In this reaction acetone is protected as acetal by using ethylene glycol. Acetals are less stable compound.

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  7

In acidic condition, an aldehyde or a ketone reacts with two molecules of alcohol or a molecule of diol to form acetal or cyclic acetal respectively.

General scheme:

EBK ORGANIC CHEMISTRY AS A SECOND LANGU, Chapter 19.5, Problem 9ATS , additional homework tip  8

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Chapter 19 Solutions

EBK ORGANIC CHEMISTRY AS A SECOND LANGU

Ch. 19.5 - Prob. 9ATSCh. 19.5 - Prob. 10CCCh. 19.5 - Prob. 11CCCh. 19.5 - Prob. 12CCCh. 19.5 - Prob. 13CCCh. 19.6 - Prob. 3LTSCh. 19.6 - Prob. 14PTSCh. 19.6 - Prob. 15PTSCh. 19.6 - Prob. 16ATSCh. 19.6 - Prob. 17CCCh. 19.6 - Prob. 18CCCh. 19.6 - Prob. 20PTSCh. 19.6 - Prob. 21ATSCh. 19.6 - Prob. 22CCCh. 19.7 - Prob. 5LTSCh. 19.7 - Prob. 23PTSCh. 19.7 - Prob. 24ATSCh. 19.7 - Prob. 25CCCh. 19.8 - Prob. 26CCCh. 19.8 - Prob. 27CCCh. 19.9 - Prob. 28CCCh. 19.9 - Prob. 29CCCh. 19.10 - Prob. 30CCCh. 19.10 - Prob. 31CCCh. 19.10 - Prob. 32CCCh. 19.10 - Prob. 33CCCh. 19.10 - Prob. 6LTSCh. 19.10 - Prob. 34PTSCh. 19.10 - Prob. 35PTSCh. 19.10 - Prob. 36ATSCh. 19.10 - Prob. 37ATSCh. 19.10 - Prob. 38CCCh. 19.11 - Prob. 39CCCh. 19.12 - Prob. 7LTSCh. 19.12 - Prob. 40PTSCh. 19.12 - Prob. 41ATSCh. 19.13 - Prob. 42CCCh. 19 - Prob. 43PPCh. 19 - Prob. 44PPCh. 19 - Prob. 45PPCh. 19 - Prob. 46PPCh. 19 - Prob. 47PPCh. 19 - Prob. 48PPCh. 19 - Prob. 49PPCh. 19 - Prob. 50PPCh. 19 - Prob. 51PPCh. 19 - Prob. 52PPCh. 19 - Prob. 53PPCh. 19 - Prob. 54PPCh. 19 - Prob. 55PPCh. 19 - Prob. 56PPCh. 19 - Prob. 57PPCh. 19 - Prob. 58PPCh. 19 - Prob. 59PPCh. 19 - Prob. 60PPCh. 19 - Predict the major product(s) obtained when each of...Ch. 19 - Prob. 62PPCh. 19 - Prob. 63PPCh. 19 - Prob. 64PPCh. 19 - Prob. 65PPCh. 19 - Prob. 66PPCh. 19 - Prob. 67PPCh. 19 - Prob. 68PPCh. 19 - Prob. 69PPCh. 19 - Prob. 70PPCh. 19 - Prob. 71PPCh. 19 - Prob. 72PPCh. 19 - Prob. 73PPCh. 19 - Prob. 74IPCh. 19 - Prob. 75IPCh. 19 - Prob. 76IPCh. 19 - Prob. 77IPCh. 19 - Prob. 78IPCh. 19 - Prob. 79IPCh. 19 - Prob. 80IPCh. 19 - Prob. 81IPCh. 19 - Prob. 83IPCh. 19 - Prob. 84IPCh. 19 - Prob. 85IPCh. 19 - Prob. 86IPCh. 19 - Prob. 87IPCh. 19 - Prob. 88IPCh. 19 - Prob. 89IPCh. 19 - Prob. 90IPCh. 19 - Prob. 91IPCh. 19 - Prob. 92IPCh. 19 - Prob. 93IPCh. 19 - Prob. 94CPCh. 19 - Prob. 95CPCh. 19 - Treatment of the following ketone with LiAIHa...
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