Explanation Given information: The period ( τ n ) of simple pendulum is 2 s. The amplitude ( θ m ) is 90 ° . Assume the acceleration due to gravity ( g ) is 32.2 ft/s 2 . Calculation: Write the expression for period ( τ n ) using the equation for large oscillation: τ n = ( 2 K π ) ( 2 π l g ) Rewrite the above equation for length ( l ). τ n = ( 2 K π ) ( 2 π l g ) τ n × ( π 2 K ) = ( 2 π l g ) l = ( τ n ( π 2 K ) 2 π ) 2 g (1) Refer Table 19

Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9781259639272

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 19.1, Problem 19.36P

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The length (l) in inches of a simple pendulum which oscillates with the period (τn) of 2 sec and an amplitude (θm) of 90°.

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Chapter 19.1, Problem 19.35P

Chapter 19.2, Problem 19.37P

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Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

Ch. 19.1 - A particle moves in simple harmonic motion....Ch. 19.1 - Prob. 19.2P Ch. 19.1 - Prob. 19.3P Ch. 19.1 - Prob. 19.4P Ch. 19.1 - Prob. 19.5P Ch. 19.1 - Prob. 19.6P Ch. 19.1 - Prob. 19.7P Ch. 19.1 - Prob. 19.8P Ch. 19.1 - Prob. 19.9P Ch. 19.1 - Prob. 19.10P

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The length ( l ) in inches of a simple pendulum which oscillates with the period ( τ n ) of 2 sec and an amplitude ( θ m ) of 90 ° .

Solution Summary: The author calculates the length (l) in inches of a simple pendulum which oscillates with the period (tau_n) of 2 sec and an amplitude

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The length (l) in inches of a simple pendulum which oscillates with the period (τn) of 2 sec and an amplitude (θm) of 90°.

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Chapter 19 Solutions