Explanation Explanation Half-life t 1 / 2 is 31.4 yrs The decay constant is calculated by the formula, λ = 0.693 t 1 / 2 Where λ is the decay constant. t 1 / 2 is the half-life. Substitute the value of t 1 / 2 in the above equation. λ = 0.693 31.4 yrs - 1 = 0 . 0 2 2 0 y r s - 1 _ The decay constant is 0 . 0 2 2 0 y r s - 1 _ . Explanation The first order integrated rate law is, ln ( n 0 n ) = λ t Where, n 0 is the initial amount of nuclide

Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition

10th Edition

ISBN: 9781305957510

Author: ZUMDAHL, Steven S.; Zumdahl, Susan A.; DeCoste, Donald J.

Publisher: Cengage Learning

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Question

Chapter 19, Problem 71AE

Interpretation Introduction

Interpretation: Half-life of a nuclide is given. Third life of the nuclide is to be defined and determined.

Concept introduction: A process through which a unstable nuclide looses its energy due to excess of protons or neutrons is known as radioactive decay. The cause of instability of a nuclide is its inefficiency in holding the nucleus together.

Half life of radioactive sample is defined as the time required for the number of nuclides to reach half of the original value.

To determine: The third life of the nuclide.

Expert Solution & Answer

Chapter 19 Solutions

Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition

Ch. 19 - Prob. 1RQ Ch. 19 - Prob. 2RQ Ch. 19 - Prob. 3RQ Ch. 19 - Prob. 4RQ Ch. 19 - Prob. 5RQ Ch. 19 - Prob. 6RQ Ch. 19 - Prob. 7RQ Ch. 19 - Prob. 8RQ Ch. 19 - Prob. 9RQ Ch. 19 - Prob. 10RQ

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Define the term half-life and illustrate it with an example.

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