Explanation Explanation The atomic mass of 2 4 He is 4 .00260 amu . The atomic mass of 1 2 He is 2 .01410 amu . The atomic mass of 1 3 He is 3 .01605 amu The mass of neutron is 1.0087 amu Number of protons in 2 4 He = 2 Number of neutron in 2 4 He = 2 Number of electrons in 2 4 He = 2 The given reaction for which the energy is to be calculated is, 1 2 H + 1 3 H → 2 4 He + 1 0 n The mass defect is calculated by the formula, Δ m = ( [ Mass of 2 4 He nucleus + Mass of neutron ] − [ Mass of 1 2 H nucleus + Mass of 1 3 H nucleus ] ) Substitute the value of the atomic mass 1 2 H , atomic mass of 2 4 He , atomic mass of 1 3 He , the number of protons and and that of the neutron in the above equation. Δ m = [ 4 .00260 + 1 .00866 ] − [ 2.0140 − 3.01605 ] Δ m = - 0 . 0 1 8 9 9 a m u _ Explanation The conversion of amu / nucleus to Kg/nucleus is done as, 1 amu = 1.66 × 10 − 27 Kg Therefore, the conversion of − 0.589 amu / nucleus into kg/nucleus is, − 0.01899 amu / nucleus = ( − 0.01899 × 1.66 × 10 − 27 ) kg/nucleus = − 3.14 × 10 − 29 kg/nucleus The binding energy per nucleon is calculated by Einstein’s mass energy equation, that is, Δ E = Δ m ⋅ C 2 Where, Δ E is the change in energy

Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition

10th Edition

ISBN: 9781305957510

Author: ZUMDAHL, Steven S.; Zumdahl, Susan A.; DeCoste, Donald J.

Publisher: Cengage Learning

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Question

Chapter 19, Problem 56E

Interpretation Introduction

Interpretation: The amount of energy released per 24He nucleus and per mole of 24He produced in the given reaction is to be calculated.

Concept introduction: The sum of masses of the component nucleons and the actual mass of a nucleus is known as the mass defect and it can be used to calculate the nuclear binding energy.

To determine: The amount of energy released per 24He nucleus and per mole of 24He produced in the given reaction.

Expert Solution & Answer

Chapter 19 Solutions

Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition

Ch. 19 - Prob. 1RQ Ch. 19 - Prob. 2RQ Ch. 19 - Prob. 3RQ Ch. 19 - Prob. 4RQ Ch. 19 - Prob. 5RQ Ch. 19 - Prob. 6RQ Ch. 19 - Prob. 7RQ Ch. 19 - Prob. 8RQ Ch. 19 - Prob. 9RQ Ch. 19 - Prob. 10RQ

Ch. 19 - Prob. 1Q Ch. 19 - Prob. 3Q Ch. 19 - Prob. 4Q Ch. 19 - Prob. 5Q Ch. 19 - Prob. 6Q Ch. 19 - Prob. 7Q Ch. 19 - Prob. 8Q Ch. 19 - Prob. 9Q Ch. 19 - Prob. 10Q Ch. 19 - Prob. 11Q Ch. 19 - Prob. 12Q Ch. 19 - Prob. 13Q Ch. 19 - Prob. 14Q Ch. 19 - Prob. 15E Ch. 19 - Prob. 16E Ch. 19 - Prob. 17E Ch. 19 - Prob. 18E Ch. 19 - Prob. 19E Ch. 19 - Prob. 20E Ch. 19 - Prob. 21E Ch. 19 - Prob. 22E Ch. 19 - Prob. 23E Ch. 19 - Prob. 24E Ch. 19 - Prob. 27E Ch. 19 - Prob. 28E Ch. 19 - Prob. 29E Ch. 19 - Prob. 30E Ch. 19 - Prob. 32E Ch. 19 - Prob. 34E Ch. 19 - Prob. 35E Ch. 19 - Prob. 36E Ch. 19 - Prob. 37E Ch. 19 - Prob. 38E Ch. 19 - Prob. 39E Ch. 19 - Prob. 40E Ch. 19 - Prob. 41E Ch. 19 - Prob. 42E Ch. 19 - Prob. 43E Ch. 19 - Prob. 44E Ch. 19 - Prob. 45E Ch. 19 - Prob. 46E Ch. 19 - Prob. 47E Ch. 19 - Prob. 48E Ch. 19 - Prob. 49E Ch. 19 - Prob. 50E Ch. 19 - Prob. 52E Ch. 19 - Prob. 53E Ch. 19 - Prob. 54E Ch. 19 - Prob. 55E Ch. 19 - Prob. 56E Ch. 19 - Prob. 57E Ch. 19 - Prob. 58E Ch. 19 - Prob. 59E Ch. 19 - Prob. 60E Ch. 19 - Prob. 61E Ch. 19 - Prob. 62E Ch. 19 - Prob. 63E Ch. 19 - Prob. 64E Ch. 19 - Prob. 65AE Ch. 19 - Prob. 66AE Ch. 19 - Prob. 67AE Ch. 19 - Prob. 68AE Ch. 19 - Prob. 69AE Ch. 19 - Prob. 70AE Ch. 19 - Prob. 71AE Ch. 19 - Prob. 72AE Ch. 19 - Prob. 73AE Ch. 19 - Prob. 74AE Ch. 19 - Prob. 75AE Ch. 19 - Prob. 76AE Ch. 19 - Prob. 77AE Ch. 19 - Prob. 78AE Ch. 19 - Prob. 79AE Ch. 19 - Prob. 80AE Ch. 19 - Prob. 81CWP Ch. 19 - Prob. 82CWP Ch. 19 - Prob. 83CWP Ch. 19 - Prob. 84CWP Ch. 19 - Prob. 85CWP Ch. 19 - Prob. 86CWP Ch. 19 - Prob. 87CP Ch. 19 - Prob. 88CP Ch. 19 - Prob. 89CP Ch. 19 - Prob. 90CP Ch. 19 - Prob. 91CP Ch. 19 - Prob. 92CP Ch. 19 - Prob. 93CP Ch. 19 - Prob. 94CP Ch. 19 - Prob. 95IP Ch. 19 - Prob. 96IP

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