BIOCHEM-ACHIEVE(FIRST DAY DISCOUNTED)
9th Edition
ISBN: 2818000069358
Author: BERG
Publisher: MAC HIGHER
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Chapter 19, Problem 6P
Interpretation Introduction
Interpretation:
The reason forhuman beings to not produce energy by photosynthesis, however, this process is critical to our survival needs to be explained.
Concept Introduction:
Photosynthesis is a process that harnesses the energy in sunlight to make sugar from water and carbon dioxide in the presence of a green pigment called chlorophyll.
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3. (15 points) Living cells homogeneously distributed
(immobilized) with an agarose gel require glucose to survive.
An important aspect of the biochemical system design is the
effective diffusion coefficient of glucose (A) into the cell-
immobilized gel. Consider the experiment shows below where
a slab of the cell-immobilized gel of 1.0cm thickness is placed
within a well-mixed aqueous solution of glucose maintained at
a concentration of 50 mmol/L. The glucose consumption
within the cell-immobilized gel proceeds by a zero-order
process given by R₁ = -0.05 mmol/(L min). The solubilities of
glucose in both the water and the gel are the same; that is, the
concentration of the glucose on the water side of the water-gel
interface is equal to the concentration of the glucose on the gel
side of the water gel interface. A syringe is mounted at the
center of the gel carefully excises a tiny sample of the gel for
glucose analysis.
A
Well mixed solution
Constant
concentration
50nmol/L
Living…
Two tetrapeptides were isolated from a possum's sweat glands. These peptides were sequenced using Edman degradation and the following 2 sequences were obtained:
Gly-Asp-Ala-Leu
Gly-Asp-Asp-Leu
Can you please help show the titration curve for both of these peptides and calculate the PI?
Two tetrapeptides were isolated from a possum's sweat glands. These peptides were sequenced using Edman degradation and the following 2 sequences were obtained:
Gly-Asp-Ala-Leu
Gly-Asp-Asp-Leu
What is the structure of the PTH derivative produced during the last round of amino acid sequencing?
Chapter 19 Solutions
BIOCHEM-ACHIEVE(FIRST DAY DISCOUNTED)
Ch. 19 - Prob. 1PCh. 19 - Prob. 2PCh. 19 - Prob. 3PCh. 19 - Prob. 4PCh. 19 - Prob. 5PCh. 19 - Prob. 6PCh. 19 - Prob. 7PCh. 19 - Prob. 8PCh. 19 - Prob. 9PCh. 19 - Prob. 10P
Ch. 19 - Prob. 11PCh. 19 - Prob. 12PCh. 19 - Prob. 13PCh. 19 - Prob. 14PCh. 19 - Prob. 15PCh. 19 - Prob. 16PCh. 19 - Prob. 17PCh. 19 - Prob. 18PCh. 19 - Prob. 19PCh. 19 - Prob. 20PCh. 19 - Prob. 21PCh. 19 - Prob. 22PCh. 19 - Prob. 23PCh. 19 - Prob. 24PCh. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - Prob. 28PCh. 19 - Prob. 29PCh. 19 - Prob. 30PCh. 19 - Prob. 31P
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- What is the primary sequence of this undecapeptide? Also, if x-ray crystallography shows a highly stable hairpin turn within the polypeptide, what about the primary sequence explains this structural feature?arrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H H ⚫OH HO- -H H- -OH H- -OH CH2OH Ag*, NH4OH, H2O Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H₂O -OH H ⚫OH HO H HO- CH2OH Cu2+ Draw Fischer Projectionarrow_forward
- Draw the product of this reaction. Ignore inorganic byproducts. H、 H -OH H ⚫OH H -OH CH2OH Fehlings' solution ⑤ Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. HO C=0 H ⚫OH H ⚫OH HO- H HO H CH2OH Tollens' solution Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H-C=O HO H HO H H- ⚫OH HO H CH2OH HNO3, H2O Draw Fischer Projectionarrow_forward
- Draw the product of this reaction. Ignore inorganic byproducts. HO HO- HO H HO ∙H HO CH2OH NaBH4, CH3OH Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. Но сво HO H HO H H OH H -OH CH2OH H2 Pd Draw Fischer Projectionarrow_forwardDraw the Haworth projection for Gulose-ẞ-1,6-sorbose and answer the following questions. (Gulose will be in the pyranose form and Sorbose will be in the furanose form) a. Label the reducing and nonreducing ends of the disaccharide b. Label the glycosidic bond c. Circle the anomeric carbons and label them as hemiacetals or acetals. d. Can this disaccharide undergo mutarotation?arrow_forward
- Draw the product of the reaction below. Ignore inorganic byproducts. H OH HO HO HO ·H H OH H OH excess CH3CH2I KOHarrow_forwardDraw the Haworth structures for the following: a. α-D-Gulopyranose b. ẞ-D-Sorbofuranose c. The two possible isomers of a-D-altrose (furanose and pyranose forms)arrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. HO H ⚫OH HO- ∙H H- -OH H ⚫OH CH2OH HNO3, H2Oarrow_forward
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