(a)
Interpretation:
Product of the given tertiary
Concept Introduction:
Cope elimination:
When tertiary amine reacts with hydrogen peroxide, it forms tertiary amine oxides which then undergo a reaction similar to Hoffmann elimination reaction is called Cope elimination.
The nitrogen atom in the tertiary amine acts as a nucleophile and attacks an oxygen atom of peroxide that results in the formation of hydroxyl ammonium ion along with hydroxide ion, this ion under goes an elimination reaction to gives an
(b)
Interpretation:
Product of the given tertiary amine reacts with hydrogen peroxide followed by heat has to be given.
Concept Introduction:
Cope elimination:
When tertiary amine reacts with hydrogen peroxide, it forms tertiary amine oxides which then undergo a reaction similar to Hoffmann elimination reaction is called Cope elimination.
The nitrogen atom in the tertiary amine acts as a nucleophile and attacks an oxygen atom of peroxide that results in the formation of hydroxyl ammonium ion along with hydroxide ion, this ion under goes an elimination reaction to gives an alkene with tertiary amine.
(c)
Interpretation:
Product of the given tertiary amine reacts with hydrogen peroxide followed by heat has to be given.
Concept Introduction:
Cope elimination:
When tertiary amine reacts with hydrogen peroxide, it forms tertiary amine oxides which then undergo a reaction similar to Hoffmann elimination reaction is called Cope elimination.
The nitrogen atom in the tertiary amine acts as a nucleophile and attacks an oxygen atom of peroxide that results in the formation of hydroxyl ammonium ion along with hydroxide ion, this ion under goes an elimination reaction to gives an alkene with tertiary amine.
(d)
Interpretation:
Product of the given tertiary amine reacts with hydrogen peroxide followed by heat has to be given.
Concept Introduction:
Cope elimination:
When tertiary amine reacts with hydrogen peroxide, it forms tertiary amine oxides which then undergo a reaction similar to Hoffmann elimination reaction is called Cope elimination.
The nitrogen atom in the tertiary amine acts as a nucleophile and attacks an oxygen atom of peroxide that results in the formation of hydroxyl ammonium ion along with hydroxide ion, this ion under goes an elimination reaction to gives an alkene with tertiary amine.
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Chapter 19 Solutions
Organic Chemistry Study Guide and Solutions Manual, Books a la Carte Edition (8th Edition)
- H2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward
- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
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