EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 9780100793439
Author: KALPAKJIAN
Publisher: YUZU
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Chapter 19, Problem 27QLP
Can thermosetting plastics be used in injection molding? Explain.
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Chapter 19 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 19 - What are the forms of raw materials for processing...Ch. 19 - What is extrusion? What products are produced by...Ch. 19 - Describe the features of an extruder screw and...Ch. 19 - How are injection-molding machines rated?Ch. 19 - What is (a) a parison, (b) a plastisol, and (c) a...Ch. 19 - How is thin plastic film produced?Ch. 19 - List several common products that can be made by...Ch. 19 - What similarities and differences are there...Ch. 19 - Explain the difference between potting and...Ch. 19 - What is thermoforming?
Ch. 19 - Describe runner, gate, sprue, and well.Ch. 19 - Describe the advantages of cold-forming plastics...Ch. 19 - What are the characteristics of filament-wound...Ch. 19 - Describe the methods that can be used to make...Ch. 19 - What is pultrusion? Pulforming?Ch. 19 - How are very thin plastic film produced?Ch. 19 - What process is used to make foam drinking cups?Ch. 19 - If a polymer is in the form of a thin sheet, is it...Ch. 19 - How are polymer fibers made? Why are they much...Ch. 19 - What are the advantages of coextrusion?Ch. 19 - Explain how latex rubber gloves are made.Ch. 19 - Describe the features of a screw extruder...Ch. 19 - Explain why injection molding is capable of...Ch. 19 - Prob. 24QLPCh. 19 - Explain the reasons that some plastic-forming...Ch. 19 - Describe the problems involved in recycling...Ch. 19 - Can thermosetting plastics be used in injection...Ch. 19 - Inspect some plastic containers, such as those...Ch. 19 - An injection-molded nylon gear is found to contain...Ch. 19 - Explain why operations such as blow molding and...Ch. 19 - Prob. 31QLPCh. 19 - Typical production rates are given in Table 19.2....Ch. 19 - What determines the cycle time for (a) injection...Ch. 19 - Does the pull-in defect (sink marks) shown in Fig....Ch. 19 - What determines the intervals at which the...Ch. 19 - Identify processes that would be suitable for...Ch. 19 - Identify processes that are capable of producing...Ch. 19 - Inspect several electrical components, such as...Ch. 19 - Inspect several similar products that are made of...Ch. 19 - What are the advantages of using whiskers a...Ch. 19 - Construct a table that lists the main...Ch. 19 - Estimate the die-clamping force required for...Ch. 19 - A 2-Iitcr plastic beverage bottle is made by blow...Ch. 19 - Consider a Styrofoam drinking cup. Measure the...Ch. 19 - In Fig. 19.2, what flight angle, , should be used...Ch. 19 - Make a survey of a variety of sports equipment,...Ch. 19 - Explain the design considerations involved in...Ch. 19 - Give examples of several parts suitable for insert...Ch. 19 - Give other examples of design modifications in...Ch. 19 - With specific examples, discuss the design issues...Ch. 19 - Die swell in extrusion is radially uniform for...Ch. 19 - Inspect various plastic components in a typical...Ch. 19 - It is well known that plastic forks, spoons, and...Ch. 19 - Prob. 55SDPCh. 19 - Make a survey of the technical literature, and...Ch. 19 - Prob. 57SDPCh. 19 - Prob. 58SDPCh. 19 - Prob. 59SDPCh. 19 - Examine some common and colorful plastic poker...Ch. 19 - Obtain different styles of toothpaste tubes,...Ch. 19 - By incorporating small amounts of blowing agent,...
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- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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