Physics for Scientists and Engineers
Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 19, Problem 1P

(a)

To determine

The energy equivalent in joules for one jelly doughnut.

(a)

Expert Solution
Check Mark

Answer to Problem 1P

The energy equivalent in joules for one jelly doughnutis 2.26×106J .

Explanation of Solution

Given information:

Mass of the woman is 55.0kg and energy in one doughnut is 540Calorie(540kcal) .

The conversion of kcal into joules is,

1kcal=4.186×103J

Therefore, the conversion of 540kcal into joules is,

540kcal=540kcal×4.186×103J1kcal=2.26×106J

Conclusion:

Therefore, the energy equivalent in joules for one jelly doughnut is 2.26×106J .

(b)

To determine

The number of steps woman must climb to change the required potential energy.

(b)

Expert Solution
Check Mark

Answer to Problem 1P

The number of steps woman must climb to change the required potential energy is 2.8×104steps .

Explanation of Solution

Given information:

Mass of the woman is 55.0kg and energy in one doughnut is 540Calorie(540kcal) . The height of a single stair is 15.0cm .

Formula to calculate the change in potential energy to climb one step is,

ΔU=mgh

  • h is the height of one step.
  • U is the gravitational potential energy.
  • m is the mass of the woman.
  • g is the acceleration due to gravity.

Formula to calculate the total change in potential energy is,

ΔUtotal=nmgh

  • n is the number of steps.

Rearrange the above equation for n .

n=ΔUtotalmgh

Substitute 2.26×106J for ΔUtotal , 55.0kg for m , 9.8m/s2 for g and 15.0cm for h to find n .

n=2.26×106J55.0kg×9.8m/s2×(15.0cm×102m1cm)=2.8×104steps

Conclusion:

Therefore, the number of steps woman must climb to change the required potential energy is 2.8×104steps .

(c)

To determine

The number of steps woman must climb to work off her breakfast.

(c)

Expert Solution
Check Mark

Answer to Problem 1P

The number of steps woman must climb to work off her breakfast is 6.99×103steps .

Explanation of Solution

Given information:

Mass of the woman is 55.0kg and energy in one doughnut is 540Calorie(540kcal) . The height of a single stair is 15.0cm . The efficiency of the human body to convert the energy into mechanical work is 25% .

Formula to calculate the mechanical work equivalent of potential energy is,

W=25%×ΔUtotal

  • W is the mechanical work equivalent of potential energy.

Formula to calculate the number of steps must climb to work off her breakfast is,

n=Wmgh

Substitute 25%×ΔUtotal for W in the above equation.

n=25%×ΔUtotalmgh

Substitute 2.26×106J for ΔUtotal , 55.0kg for m , 9.8m/s2 for g and 15.0cm for h to find n .

n=25100×2.26×106J55.0kg×9.8m/s2×(15.0cm×102m1cm)=6.99×103steps

Conclusion:

Therefore, the number of steps woman must climb to work off her breakfast is 6.99×103steps .

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Chapter 19 Solutions

Physics for Scientists and Engineers

Ch. 19 - If water with a mass mk at temperature Tk is...Ch. 19 - An aluminum calorimeter with a mass of 100 g...Ch. 19 - An electric drill with a steel drill bit of mass m...Ch. 19 - A 3.00-g copper coin at 25.0C drops 50.0 m to the...Ch. 19 - How much energy is required to change a 40.0-g ice...Ch. 19 - Prob. 11PCh. 19 - A 3.00-g lead bullet at 30.0C is fired at a speed...Ch. 19 - In an insulated vessel, 250 g of ice at 0C is...Ch. 19 - Prob. 14PCh. 19 - One mole of an ideal gas is warmed slowly so that...Ch. 19 - (a) Determine the work done on a gas that expands...Ch. 19 - A thermodynamic system undergoes a process in...Ch. 19 - Why is the following situation impossible? An...Ch. 19 - A 2.00-mol sample of helium gas initially at 300...Ch. 19 - (a) How much work is done on the steam when 1.00...Ch. 19 - A 1.00-kg block of aluminum is warmed at...Ch. 19 - In Figure P19.22, the change in internal energy of...Ch. 19 - A student is trying to decide what to wear. His...Ch. 19 - A concrete slab is 12.0 cm thick and has an area...Ch. 19 - Two lightbulbs have cylindrical filaments much...Ch. 19 - Prob. 26PCh. 19 - (a) Calculate the R-value of a thermal window made...Ch. 19 - Prob. 28PCh. 19 - Gas in a container is at a pressure of 1.50 atm...Ch. 19 - Prob. 30APCh. 19 - You have a particular interest in automobile...Ch. 19 - You are working in a condensed-matter laboratory...Ch. 19 - Prob. 33APCh. 19 - Prob. 34APCh. 19 - Prob. 35APCh. 19 - Prob. 36APCh. 19 - An ice-cube tray is filled with 75.0 g of water....Ch. 19 - Prob. 38APCh. 19 - An iron plate is held against an iron wheel so...Ch. 19 - One mole of an ideal gas is contained in a...Ch. 19 - Prob. 41APCh. 19 - Prob. 42APCh. 19 - Prob. 43APCh. 19 - A student measures the following data in a...Ch. 19 - (a) The inside of a hollow cylinder is maintained...Ch. 19 - A spherical shell has inner radius 3.00 cm and...Ch. 19 - Prob. 47CP
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