Starting with Equation 18.11, show that the total pressure P in a container filled with a mixture of several ideal gases is P = P 1 + P 2 + P 3 + ⋯ , where P 1 , P 2 , ⋯ are the pressures that each gas would exert if it alone filled the container. (These individual pressures are called the partial pressures of the respective gases.) This result is known as Dalton’s law of partial pressures .
Starting with Equation 18.11, show that the total pressure P in a container filled with a mixture of several ideal gases is P = P 1 + P 2 + P 3 + ⋯ , where P 1 , P 2 , ⋯ are the pressures that each gas would exert if it alone filled the container. (These individual pressures are called the partial pressures of the respective gases.) This result is known as Dalton’s law of partial pressures .
Solution Summary: The author illustrates how the total pressure in a container filled with several ideal gases is given by left.
Starting with Equation 18.11, show that the total pressure P in a container filled with a mixture of several ideal gases is
P
=
P
1
+
P
2
+
P
3
+
⋯
, where
P
1
,
P
2
,
⋯
are the pressures that each gas would exert if it alone filled the container. (These individual pressures are called the partial pressures of the respective gases.) This result is known as Dalton’s law of partial pressures.
No chatgpt pls will upvote Already got wrong chatgpt answer
No chatgpt pls will upvote
Taking a Hike
A hiker begins a trip by first walking 21.0 km southeast from her car. She stops and sets up her tent for the night. On the second day, she walks 46.0 km in a direction 60.0° north of east, at which point she discovers a forest ranger's tower.
y (km)
Can
N
W-DE
45.0°
60.0°
Tent
Tower
B
x (km)
☹
(a) Determine the components of the hiker's displacement for each day.
SOLUTION
Conceptualize We conceptualize the problem by drawing a sketch as in the figure. If we denote the displacement vectors on the first and second days by A and B, respectively, and use the ---Select-- as the origin of coordinates, we obtain the vectors shown in the figure. The sketch allows us to estimate the resultant vector as shown.
Categorize Drawing the resultant R, we can now categorize this problem as one we've solved before: --Select-- of two vectors. You should now have a hint of the power of categorization in that many new problems are very similar to problems we have already solved if we are…
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