
Concept explainers
Interpretation:
Need to determine the time consumed for chrome plating of car bumper.
Concept introduction:
Chrome plating is the electrolytic deposition of chromium over another metal to protect it from rust formation. The metal to be plated was used as cathode at which the
Since the thickness and surface area of the metal was given. From which the volume of chromium coated can be attained by the following equation.
By knowing the volume, mass of chromium plated can be calculated by using the density equation.
From the mass of chromium plated, the number of moles can be calculated as shown below
From half-cell reaction it was known that two mole of chromium need twelve mole of electrons, Therefore the number of mole of electrons involved was attained using the below equation
Coulombs of charges involved in the reaction was calculated by multiplying the number of moles of electron with faraday constant.
Since current utilized was given,
So,

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Chapter 19 Solutions
General Chemistry
- In the image below, correctly name the glassware # _P ( Blank 1) and T ( Blank 2). 景 A W Blank # 1 Blank #2 1000 +19 E E D 0 0-0 G H A A K Π 12 R M N S 0-0-arrow_forwardFeedback: Your answer is incorrect. Predict the major products of the following organic reaction: CN Δ + A ? NC Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. esc Check 80 MH F1 F2 F3 F4 F5 50 @ # C % 95 € Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C A DII F6 F7 F8 7 * 8 Λ & 6 F9 F10 9 0 4arrow_forwardIncorrect Feedback: Your answer is incorrect. Predict the major products of the following organic reaction: ཤིགས་བྱ རྩ་ཅད་ཀྱིས་༢༩ + Some important notes: A ^ ? • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. E Check 0 لا Save For La ©2025 McGraw Hill LLC. All Rights Reserved. Terms of All F9 Aarrow_forward
- Predict the major products of the following organic reaction: + Δ A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privaarrow_forwardesc 2 Incorrect Feedback: Your answer is incorrect. Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? A O • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. . If your answer is no, check the box under the drawing area instead. Check F1 ! @ X C Save For Later Submit Assignment 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 80 et A ད 1 4 F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 # $ 45 % A 6 87 & * 8 9 ) 0 + ||arrow_forwardCan the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ?A Δ O • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilit ku F11arrow_forward
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