The first-order rate constant for the given reaction has to be determined. Concept introduction: Order of a reaction: The sum of exponents of the concentrations in the rate law for the reaction is said to be order of a reaction. Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants). It is also said to be as rate equation . Half-life: The time required for half of a reactant to be consumed in a reaction is said to be half-life. Half-life of a reaction is represented by the symbol as t 1 2

Question

Want to see the full answer?

Answer 1

Question

Chapter 19, Problem 19.30QP

(a)

Interpretation Introduction

Interpretation:

The first-order rate constant for the given reaction has to be determined.

Concept introduction:

Order of a reaction: The sum of exponents of the concentrations in the rate law for the reaction is said to be order of a reaction.

Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants). It is also said to be as rate equation.

Half-life: The time required for half of a reactant to be consumed in a reaction is said to be half-life.

Half-life of a reaction is represented by the symbol as t12

(b)

Interpretation Introduction

Interpretation:

(a) The first-order rate constant for the given reaction has to be determined.

(b) The time required for 15% of the phosphine to decompose has to be determined.

Concept introduction:

Order of a reaction: The sum of exponents of the concentrations in the rate law for the reaction is said to be order of a reaction.

Rate law: It is an equation that related to the rate of reaction to the concentrations or pressures of substrates (reactants). It is also said to be as rate equation.

Half-life: The time required for half of a reactant to be consumed in a reaction is said to be half-life.

Half-life of a reaction is represented by the symbol as t12

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Don't used hand raiting and don't used Ai solution

13.84. Chlorine atoms react with methane, forming HCI and CH3. The rate constant for the reaction is 6.0 × 107 M¹ s¹ at 298 K. When the experiment was run at three other temperatures, the following data were collected: T (K) k (M-1 s-1) 303 6.5 × 107 308 7.0 × 107 313 7.5 x 107 a. Calculate the values of the activation energy and the frequency factor for the reaction. b. What is the value of the rate constant in the lower stratosphere, where T = 218 K?

My Organic Chemistry textbook says about the formation of cyclic hemiacetals, "Such intramolecular reactions to form five- and six-membered rings are faster than the corresponding intermolecular reactions. The two reacting functional groups, in this case OH and C=O, are held in close proximity, increasing the probability of reaction."According to the book, the formation of cyclic hemiacetals occurs in acidic conditions. So my question is whether the carbonyl group in this reaction reacts first with the end alcohol on the same molecule or with the ethylene glycol. And, given the explanation in the book, if it reacts first with ethylene glycol before its own end alcohol, why would it? I don't need to know the final answer. I need to know WHY it would not undergo an intermolecular reaction prior to reacting with the ethylene glycol if that is the case. Please do not use an AI answer.