Explanation For the given cell, pH of the cell is calculated by using the Nernst equation. According to the Nernst equation E c e l l = E c e l l º − 0.0592 n log Q For the given question E c e l l º = E r e d º − E o x i º From the reduction potential values A u 3 + / A u = 1.50 V a n d H + / H 2 = 0 V Thus E c e l l º = 1.50 V − 0 V = 1.50 V It is mentioned that E c e l l = 1

Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: A Molecular Approach (4th Edition)

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ISBN: 9780134162430

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 19, Problem 112E

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Interpretation: The concentration of Au³⁺ present in the solution is to be calculated.

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Chapter 19, Problem 111E

Chapter 19, Problem 113E

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Chapter 19 Solutions

Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: A Molecular Approach (4th Edition)

Ch. 19 - Prob. 1SAQ Ch. 19 - Q2. Which statement is true for voltaic cells? a)...Ch. 19 - Prob. 3SAQ Ch. 19 - Prob. 4SAQ Ch. 19 - Prob. 5SAQ Ch. 19 - Prob. 6SAQ Ch. 19 - Prob. 7SAQ Ch. 19 - Prob. 8SAQ Ch. 19 - Prob. 9SAQ Ch. 19 - Prob. 10SAQ

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The concentration of Au 3+ present in the solution is to be calculated.

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Interpretation: The concentration of Au3+ present in the solution is to be calculated.

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Chapter 19 Solutions

Interpretation: The concentration of Au³⁺ present in the solution is to be calculated.