Explanation Right hand rule: To determine the direction of the magnetic force on a positive moving charge, thumb of the right hand points in the direction of velocity, the fingers in the direction of magnetic field and a perpendicular to the palm points in the direction of force. The figure 1 shows the direction of the force on the electrons moves in the positive x direction. From the figure, the magnetic field at the electron acts into the page, the force acting on the electron is in the positive x direction. Write the expression for magnetic force on the electron. F = q v B sin θ (I) Here, F is the magnetic force, q is the charge of the electron, v is the speed of the electron, and B is the magnetic field, and θ is the angle. Write the expression for magnetic field due to long straight wire. B = μ 0 I 2 π r (II) Here, B is the magnetic field, μ 0 is the permeability in vacuum, I is the current, and r is the radius of the loop. Conclusion: Substitute equation (II) in equation (I). F = q v μ 0 I 2 π r sin θ Substitute 1.602 × 10 − 19 C for q , 1.00 × 10 7 m/s for v , 4 π × 10 − 7 T ⋅ m/A for μ 0 , 4

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ISBN: 2818440038631

Author: GIAMBATTISTA

Publisher: MCG

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Chapter 19, Problem 102P

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The magnetic force on the electron.

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Chapter 19, Problem 101P

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Chapter 19 Solutions

PHYSICS

Ch. 19.2 - 19.2 An electron is moving with speed v in a...Ch. 19.2 - 19.1 Acceleration of Cosmic Ray Particle If v =...Ch. 19.2 - 19.2 Magnetic Force on an Electron Find the...Ch. 19.2 - Practice Problem 19.3 Velocity Component Parallel...Ch. 19.3 - 19.4 Ion Speed The magnetic field used in the mass...Ch. 19.3 - 19.5 Increasing Kinetic Energy in a Proton...Ch. 19.4 - 19.4 A particle’s helical motion is shown in Fig....Ch. 19.5 - 19.5 (a) , points east, and q is negative, so ...Ch. 19.5 - Practice Problem 19.6 Deflection of a Particle...Ch. 19.5 - Prob. 19.7PP

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