ORGANIC CHEMISTRY-EBOOK>I<
ORGANIC CHEMISTRY-EBOOK>I<
9th Edition
ISBN: 9781305084414
Author: McMurry
Publisher: INTER CENG
Question
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Chapter 18.SE, Problem 24MP
Interpretation Introduction

a)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  1

Interpretation:

The products formed and the mechanism by which they are formed when tert-butyl ethyl ether is treated with HBr is to be given.

Concept introduction:

Ethers are cleaved by strong acids. The cleavage takes place either by SN1 or SN2 mechanisms, depending upon the structure of the substrate. Ethers with only primary and secondary alkyl groups react by SN2 mechanism. The Br- or I- attacks the protonated ether at the less hindered side to yield a single alcohol and a single alkyl halide. Ethers with a tertiary, benzylic or an allylic group cleave either by SN1 or E1 mechanism because these can produce a stable carbocations yielding alkenes and alcohols.

To give:

The products formed and the mechanism by which they are formed when tert-butyl ethyl ether is treated with HBr is to be given.

Expert Solution
Check Mark

Answer to Problem 24MP

The products formed when tert-butyl ethyl ether is treated with HBr are ethanol and tert-butylbromide.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  2

Explanation of Solution

The reaction occurs following SN1 mechanism. The acid protonates the ether initially and the protonated ether eliminates ethanol to produce a stable tert-butyl carbocation. In the next step the bromide ion attacks the carbocation to yield tert-butyl bromide as the product.

Conclusion

The products formed when tert-butyl ethyl ether is treated with HBr are ethanol and tert-butylbromide.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  3

Interpretation Introduction

b)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  4

Interpretation:

The products formed and the mechanism by which they are formed when tert-butyl phenyl ether is treated with HBr is to be given.

Concept introduction:

Ethers are cleaved by strong acids. The cleavage takes place either by SN1 or SN2 mechanisms, depending upon the structure of the substrate. Ethers with only primary and secondary alkyl groups react by SN2 mechanism. The Br- or I- attacks the protonated ether at the less hindered side to yield a single alcohol and a single alkyl halide. Ethers with a tertiary, benzylic or an allylic group cleave either by SN1 or E1 mechanism because these can produce a stable carbocations yielding alkenes and alcohols.

To give:

The products formed and the mechanism by which they are formed when tert-butyl phenyl ether is treated with HBr.

Expert Solution
Check Mark

Answer to Problem 24MP

The products formed when tert-butyl phenyl ether is treated with HBr are phenol and tert-butyl bromide.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  5

Explanation of Solution

The reaction occurs following SN1 mechanism. The acid protonates the ether initially and the protonated ether eliminates phenol to produce a stable tert-butyl carbocation. In the next step the bromide ion attacks the carbocation to yield tert-butyl bromide.

Conclusion

The products formed when tert-butyl phenyl ether is treated with HBr are phenol and tert-butyl bromide.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  6

Interpretation Introduction

c)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  7

Interpretation:

The products formed and the mechanism by which they are formed when tert-butyl isopropyl ether is treated with HI is to be given.

Concept introduction:

Ethers are cleaved by strong acids. The cleavage takes place either by SN1 or SN2 mechanisms, depending upon the structure of the substrate. Ethers with only primary and secondary alkyl groups react by SN2 mechanism. The Br- or I- attacks the protonated ether at the less hindered side to yield a single alcohol and a single alkyl halide. Ethers with a tertiary, benzylic or an allylic group cleave either by SN1 or E1 mechanism because these can produce a stable carbocations yielding alkenes and alcohols.

To give:

The products formed and the mechanism by which they are formed when tert-butyl isopropyl ether is treated with HI.

Expert Solution
Check Mark

Answer to Problem 24MP

The products formed when tert-butyl isopropyl ether is treated with HI are tert-butyl bromide and 2-propanol.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  8

Explanation of Solution

The reaction occurs following SN1 mechanism. The acid protonates the ether initially and the protonated ether eliminates 2-propanol to produce a stable tert-butyl carbocation. In the next step the iodide ion attacks the carbocation to yield tert-butyl iodide.

Conclusion

The products formed when tert-butyl isopropyl ether is treated with HI are tert-butyl bromide and 2-propanol.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  9

Interpretation Introduction

d)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  10

Interpretation:

The products formed and the mechanism by which they are formed when ethyl 1-methylcyclohexyl ether is treated with HI is to be given.

Concept introduction:

Ethers are cleaved by strong acids. The cleavage takes place either by SN1 or SN2 mechanisms, depending upon the structure of the substrate. Ethers with only primary and secondary alkyl groups react by SN2 mechanism. The Br- or I- attacks the protonated ether at the less hindered side to yield a single alcohol and a single alkyl halide. Ethers with a tertiary, benzylic or an allylic group cleave either by SN1 or E1 mechanism because these can produce a stable carbocations yielding alkenes and alcohols.

To give:

The products formed and the mechanism by which they are formed when ethyl 1-methylcyclohexyl ether is treated with HI.

Expert Solution
Check Mark

Answer to Problem 24MP

The products formed when ethyl 1-methylcyclohexyl ether is treated with HI are 1-iodo-1-methylcyclohexane and ethanol.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  11

Explanation of Solution

The reaction occurs following SN1 mechanism. The acid protonates the ether initially and the protonated ether eliminates ethanol to produce a stable tert-butyl carbocation. In the next step the iodide ion attacks the carbocation to yield tert-butyl iodide.

Conclusion

The products formed when ethyl 1-methylcyclohexyl ether is treated with HI are 1-iodo-1-methylcyclohexane and ethanol.

The mechanism by which they are formed is given below.

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 18.SE, Problem 24MP , additional homework tip  12

All the reactions (a), (b), (c) and (d) occur through SN1 mechanism.

All the reactions, (a), (b), (c) and (d) take place following SN1 mechanism. The protonated epoxide first loses an alcohol to yield a stable tert-butyl carbocation which is then attacked by the halide ion.

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Chapter 18 Solutions

ORGANIC CHEMISTRY-EBOOK>I<

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