Student Study Guide and Solutions Manual T/A Organic Chemistry
Student Study Guide and Solutions Manual T/A Organic Chemistry
2nd Edition
ISBN: 9781118647950
Author: David R. Klein
Publisher: WILEY
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Chapter 18.8, Problem 26CC
Interpretation Introduction

Interpretation: From the given data of IR spectrum and 1HNMR spectrum of the given molecular formula, structure and name of the compound should be given and the product should be predicted when it is treated with Birch condition.

Concept introduction:

  • In the IR spectrum, the signal just above 3000 cm-1 confirms the presence of  aromatic ring
  • Aromatic compound also produces a series of signals between 1450 and 1650 cm-1 in the IR spectrum
  • In IR spectrum,  a C=O bond will account for the signal at 1686 cm-1
  • In the 1HNMR spectrum, the signals between 6.5 and 8ppm confirms the aromatic ring. The presence of a multiplet near 7 ppm is one of the best way to verify the aromatic ring
  • The integration value of the multiplet near 7ppm indicates the extent of substitution. An integration  of 5 indicates monosubstituted ring, an integration of 4 indicates disubsituted ring
  • Birch reduction converts aromatic compound having benzoid ring in to a product 1, 4-cyclohexa diene. The product having hydrogen atoms attached on opposite end of the molecule
    • Birch reduction is the reduction of aromatic rings with sodium, potassium or lithium and an alcohol in liquid ammonia. This is unlike catalytic hydrogenation
    • When benzene with an electron donating group such as alkyl group is treated with Birch reduction, the carbon atom connected to the alkyl group is not reduced. Electron   donating effect destabilizes the radical anion.
    • When an electron withdrawing groups are used, different regiochemical outcome is observed. Electron withdrawing   effect stabilizes the intermediate.

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2. Name the following hydrocarbons. (9 marks) a) HHHHHHHH H-C-C- H-O-S b) HCEC-CH3 H H H H H d) c) H C=C- H H H e) CH3 CH3 CH2CH=CH-CH=CHCH3 HHHH H-C-C-C-C-H H HH H f) large CH2CH3 pola H3C section lovels tower, able ocart firs g) Tower H3C-CH2 then in H3C-CH-CH-CH3 enblbano bne noitsidab Copyright © 2008. Durham Continuing Education CH3
Name the molecules & Identify any chiral center CH3CH2CH2CHCH₂CH₂CH₂CH₂ OH CH₂CHCH2CH3 Br CH3 CH3CHCH2CHCH2CH3 CH3
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).

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Student Study Guide and Solutions Manual T/A Organic Chemistry

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