Brock Biology of Microorganisms (14th Edition)
14th Edition
ISBN: 9780321897398
Author: Michael T. Madigan, John M. Martinko, Kelly S. Bender, Daniel H. Buckley, David A. Stahl, Thomas Brock
Publisher: PEARSON
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Chapter 18.4, Problem 1MQ
- What structure in the cell is the target for fluorescent probes in phylogenetic FISH?
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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin
Chapter 18 Solutions
Brock Biology of Microorganisms (14th Edition)
Ch. 18.1 - Describe the enrichment strategy behind...Ch. 18.1 - Why is sulfate (So42) added to a Winogradsky...Ch. 18.1 - What is enrichment bias? How does dilution reduce...Ch. 18.2 - How does the agar dilution method differ from...Ch. 18.2 - How might you isolate a morphologically unique...Ch. 18.2 - What is meant by high-throughput in culturing...Ch. 18.3 - How does viability staining differ from stains...Ch. 18.3 - Prob. 2MQCh. 18.3 - Why is it incorrect to say that the GFP is a...Ch. 18.4 - What structure in the cell is the target for...
Ch. 18.4 - FISH and CARD-FISH can be used to reveal different...Ch. 18.5 - What could you conclude from PCR/DGGE analysis of...Ch. 18.5 - What surprising finding has come out of many...Ch. 18.6 - MINIQUIZ
• What is a phylochip and what can it...Ch. 18.6 - What are the advantages and disadvantages of...Ch. 18.6 - Prob. 3MQCh. 18.7 - Prob. 1MQCh. 18.7 - How do environmental genomic approaches differ...Ch. 18.7 - Prob. 3MQCh. 18.8 - Prob. 1MQCh. 18.8 - If a large pulse of organic matter entered the...Ch. 18.9 - Prob. 1MQCh. 18.9 - What is the simplest explanation for why lunar...Ch. 18.9 - What is the expected isotopic composition of...Ch. 18.10 - How could NanoSIMS be used to identify a...Ch. 18.10 - Prob. 2MQCh. 18.10 - How does MAR-FISH link microbial diversity and...Ch. 18.11 - How can stable isotope probing reveal the identity...Ch. 18.11 - What key method is required to do genomics on a...Ch. 18.11 - Prob. 3MQCh. 18 - Prob. 1RQCh. 18 - Prob. 2RQCh. 18 - Prob. 3RQCh. 18 - Prob. 4RQCh. 18 - Prob. 5RQCh. 18 - Prob. 6RQCh. 18 - Prob. 7RQCh. 18 - Prob. 8RQCh. 18 - Prob. 9RQCh. 18 - REVIEW QUESTIONS
10. Why is a microarray not...Ch. 18 - Prob. 11RQCh. 18 - Prob. 12RQCh. 18 - Q What are the major advantages of radioisotopic...Ch. 18 - Prob. 14RQCh. 18 - Prob. 15RQCh. 18 - REVIEW QUESTIONS
16. What is the advantage of...Ch. 18 - Prob. 17RQCh. 18 - Design an experiment for measuring the activity of...Ch. 18 - You wish to know whether Archaea exist in a lake...Ch. 18 - Design an experiment to solve the following...Ch. 18 - Design a SIP experiment that would allow you to...
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- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
- During a routine medical check up of a healthy man it was found that his haematocrit value was highly unusual – value of 60%. What one of the options below is the most likely reason? He will have a diet high in iron. He is likely to be suffering from anaemia. He lives at high altitude. He has recently recovered from an accident where he lost a lot of blood. He has a very large body size.arrow_forwardExplain what age of culture is most likely to produce an endospore?arrow_forwardExplain why hot temperatures greater than 45 degrees celsius would not initiate the sporulation process in endospores?arrow_forward
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- How many types of reactions can an enzyme perform?arrow_forwardYour goal is to produce black seeds resistant to mold. So you make the same cross again (between a homozygous black seeded, mold susceptible parent and a homozygous white seeded and mold resistant parent), and, again, advance progeny by SSD to create 100 F10 generation plants. Based on the information you obtained from your first crossing experiment (Question #4), how many F10 plants would you expect to have black seeds and be resistant to mold? Assume that a toxin produced by the mold fungus has been isolated. Only mold resistant seeds will germinate in the presence of the toxin. Could you use this toxin screening procedure to have segregation distortion work in your favor in the F2 generation? Explain your answer. Info from Question 4 a. P Locus (Seed Color): Hypothesis: The null hypothesis (H₀) is that seed color is controlled by alleles at a single locus. Observed Data: Total white seeds: 45 (resistant plants) + 6 (susceptible plants) = 51 Total black seeds: 7 (resistant…arrow_forward10. Consider the following enzyme and its substrate where the "+" and "-" indicate cations and anions, respectively. Explain which of the following inhibitors could inhibit this enzyme? Which type of inhibitor would it be and why? (Video 5-2) Substrate Enzyme Potential inhibitorsarrow_forward
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