Brock Biology of Microorganisms (14th Edition)
14th Edition
ISBN: 9780321897398
Author: Michael T. Madigan, John M. Martinko, Kelly S. Bender, Daniel H. Buckley, David A. Stahl, Thomas Brock
Publisher: PEARSON
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Chapter 18.10, Problem 2MQ
Summary Introduction
Flow cytometry is used to count and examine the mixture of various cells. The cells are suspended in a liquid or fluid and that suspension is injected into this instrument. An electron detector helps to sort cells based on defined criteria such as size, shape, and fluorescent properties of cells.
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Chapter 18 Solutions
Brock Biology of Microorganisms (14th Edition)
Ch. 18.1 - Describe the enrichment strategy behind...Ch. 18.1 - Why is sulfate (So42) added to a Winogradsky...Ch. 18.1 - What is enrichment bias? How does dilution reduce...Ch. 18.2 - How does the agar dilution method differ from...Ch. 18.2 - How might you isolate a morphologically unique...Ch. 18.2 - What is meant by high-throughput in culturing...Ch. 18.3 - How does viability staining differ from stains...Ch. 18.3 - Prob. 2MQCh. 18.3 - Why is it incorrect to say that the GFP is a...Ch. 18.4 - What structure in the cell is the target for...
Ch. 18.4 - FISH and CARD-FISH can be used to reveal different...Ch. 18.5 - What could you conclude from PCR/DGGE analysis of...Ch. 18.5 - What surprising finding has come out of many...Ch. 18.6 - MINIQUIZ
• What is a phylochip and what can it...Ch. 18.6 - What are the advantages and disadvantages of...Ch. 18.6 - Prob. 3MQCh. 18.7 - Prob. 1MQCh. 18.7 - How do environmental genomic approaches differ...Ch. 18.7 - Prob. 3MQCh. 18.8 - Prob. 1MQCh. 18.8 - If a large pulse of organic matter entered the...Ch. 18.9 - Prob. 1MQCh. 18.9 - What is the simplest explanation for why lunar...Ch. 18.9 - What is the expected isotopic composition of...Ch. 18.10 - How could NanoSIMS be used to identify a...Ch. 18.10 - Prob. 2MQCh. 18.10 - How does MAR-FISH link microbial diversity and...Ch. 18.11 - How can stable isotope probing reveal the identity...Ch. 18.11 - What key method is required to do genomics on a...Ch. 18.11 - Prob. 3MQCh. 18 - Prob. 1RQCh. 18 - Prob. 2RQCh. 18 - Prob. 3RQCh. 18 - Prob. 4RQCh. 18 - Prob. 5RQCh. 18 - Prob. 6RQCh. 18 - Prob. 7RQCh. 18 - Prob. 8RQCh. 18 - Prob. 9RQCh. 18 - REVIEW QUESTIONS
10. Why is a microarray not...Ch. 18 - Prob. 11RQCh. 18 - Prob. 12RQCh. 18 - Q What are the major advantages of radioisotopic...Ch. 18 - Prob. 14RQCh. 18 - Prob. 15RQCh. 18 - REVIEW QUESTIONS
16. What is the advantage of...Ch. 18 - Prob. 17RQCh. 18 - Design an experiment for measuring the activity of...Ch. 18 - You wish to know whether Archaea exist in a lake...Ch. 18 - Design an experiment to solve the following...Ch. 18 - Design a SIP experiment that would allow you to...
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- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
- Which ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardDuring a routine medical check up of a healthy man it was found that his haematocrit value was highly unusual – value of 60%. What one of the options below is the most likely reason? He will have a diet high in iron. He is likely to be suffering from anaemia. He lives at high altitude. He has recently recovered from an accident where he lost a lot of blood. He has a very large body size.arrow_forwardExplain what age of culture is most likely to produce an endospore?arrow_forward
- Explain why hot temperatures greater than 45 degrees celsius would not initiate the sporulation process in endospores?arrow_forwardEndospore stain: Consider tube 2 of the 7-day bacillus culture. After is was heated, it was incubated for 24 hours then refrigerated. Do you think the cloudiness in this tube is due mostly to vegetative cells or to endospores? Explain your reasoningarrow_forwardReactunts C6H12O6 (Glucose) + 2NAD+ + 2ADP 2 Pyruvic acid + 2NADH + 2ATP a. Which of the above are the reactants? b. Which of the above are the products? c. Which reactant is the electron donor? GHz 06 (glucose) d. Which reactant is the electron acceptor? NAD e. Which of the products have been reduced? NADH f. Which of the products have been oxidized? g. Which process was used to produce the ATP? h. Where was the energy initially in this chemical reaction and where is it now that it is finished? i. Where was the carbon initially in this chemical reaction and where is it now that it is finished? j. Where were the electrons initially in this chemical reaction and where is it now that it is finished? 3arrow_forward
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