Campbell Biology in Focus
3rd Edition
ISBN: 9780134710679
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Rebecca Orr
Publisher: PEARSON
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Textbook Question
Chapter 18.3, Problem 1CC
The best estimate is that the human genome contains fewer than 21,000 genes. However, there is evidence that human cells produce many more than 21,000 different polypeptides. What processes might account for this discrepancy?
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When the human genome sequence was finally completed, scientists were surprised to discover that the genome contains far fewer genes than expected. How many genes are present in the human genome? Scientists have also found that there are many more different kinds of proteins in the human cells that there are different genes in the genome. How can this be explained?
A 2500 bp region of the human genome encodes two genes. One of the genes encodes a protein of 600 amino acids and the other gene encodes a protein of 280 amino acids. The mRNA sequences of the two genes do not contain any of the same nucleotide sequences (i.e. they do not overlap). How is this possible? Fully explain your answer.
People who carry a theoretical genetic disorder (called B-disease) can be identified from a 2kb DNA sequence.People who carry this genetic disorder have a single nucleotide polymorphism that results in a change of GTATCC to GGATCC, a site that only occurs once at nucleotide number 750 in this DNA sequence. Answer the following questions based on the information provided.
(a) How can you develop a simple molecular test to identify the genetic disorder?
(b) If you have carried out the molecular test (based on the information above) on a 100 individual and found that 24 were healthy (BB) and 26 were carriers (bb);
1) What is the ratio of heterozygous?
2) Show how can you identify the three types from the agarose gel
Chapter 18 Solutions
Campbell Biology in Focus
Ch. 18.1 - Prob. 1CCCh. 18.2 - Prob. 1CCCh. 18.2 - Explain the advantage of the systems biology...Ch. 18.2 - Prob. 3CCCh. 18.3 - The best estimate is that the human genome...Ch. 18.3 - Prob. 2CCCh. 18.3 - Prob. 3CCCh. 18.4 - Discuss the characteristics of mammalian genomes...Ch. 18.4 - Which of the three mechanisms described in Figures...Ch. 18.4 - Prob. 3CC
Ch. 18.5 - Describe three examples of errors in cellular...Ch. 18.5 - Prob. 2CCCh. 18.5 - Prob. 3CCCh. 18.6 - Would you expect the genome of the macaque (a...Ch. 18.6 - Prob. 2CCCh. 18 - Prob. 1TYUCh. 18 - Prob. 2TYUCh. 18 - Two eukaryotic proteins have one domain in common...Ch. 18 - DRAW IT Comparing amino acid sequences of similar...Ch. 18 - SCIENTIFIC INQUIRY The scientists mapping human...Ch. 18 - FOCUS ON EVOLUTION Genes important in the...Ch. 18 - FOCUS ON INFORMATION The continuity of life is...Ch. 18 - SYNTHESIZE YOUR KNOWLEDGE Insects have three...
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- E. How many nucleotides would be required to generate a polypeptide that is 15 amino acids long? This requires knowing how many nucleotides of DNA code for one amino acid. F. Assuming that there are between 20,000-25,000 genes in the human genome, do you think there are 1) fewer, 2) approximately the same number, or 3) more proteins in the human genome? Explain your answer.arrow_forwardPeople who carry a theoretical genetic disorder (called B-disease) can be identified from a 2kb DNA sequence. People who carry this genetic disorder have a single nucleotide polymorphism that results in a change of GTATTC to GGATTC, a site that only occurs once at nucleotide number 750 in this DNA sequence. Answer the following questions based on the information provided. (a) How can you develop a simple molecular test to identify the genetic disorder? (b) If you have carried out the molecular test (based on the information above) on a 100 individuals and found that 24 were healthy (BB) and 26 were carriers (bb); 1) What is the ratio of heterozygous? 2) Show how can you identify the three types from the agarose gel.arrow_forwardIn a study showing that approximately 10% of protein-coding genes are essential for Cell survival .This translates into which of the following number of essential genes in the human genome .a)100 b) 500 c)1000 d)2000arrow_forward
- The human genome contains thousands of sequences known as small open reading frames, some of which encode proteins of about 30 amino acids. What is the minimum number of nucleotides required to encode such a protein?arrow_forwardWhat percentage of the DNA in the genome actually corresponds to genes? How much is actually protein-coding exons? What makes up the rest?arrow_forwardThe best estimate is that the human genome containsfewer than 21,000 genes. However, there is evidencethat human cells produce many more than 21,000 different polypeptides. What processes might account for thisdiscrepancy?arrow_forward
- Annotation of the human genome sequence reveals a discrepancy between the number of protein-coding genes and the number of predicted proteins actually expressed by the genome. Proteomic analysis indicates that human cells are capable of synthesizing more than 100,000 different proteins and perhaps three times this number. What is the discrepancy, and how can it be reconciled?arrow_forwardPeople who carry a theoretical genetic disorder (called B-disease) can be identified from a 2kb DNA sequence. People who carry this genetic disorder have a single nucleotide polymorphism that results in a change of GTATCC to GGATCC, a site that only occurs once at nucleotide number 750 in this DNA sequence. Answer the following questions based on the information provided: (a) How can you develop a simple molecular test to identify the genetic disorder (based on the information above) ? (b) If you have carried out the molecular test (based on the information above) on a 100 individual and found that 24 were healthy (BB) and 26 were carriers (bb); 1) What is the ratio of heterozygous? 2) Show how can you identify the three types from the agarose gel ? *note: the carrier means : (bb), I mean the diseased individuals who are carriers of the bb genotype.arrow_forwardYour advisor, a brilliant bioinformatician, has high regard for your intellect and industry. she suggests that you write a computer program that will identify the exons of protein- coding genes directly from the sequence of the human genome. In preparation for that task, you decide to write down a list of the features that might distinguish protein- coding sequences from intronic DNA and from other sequences in the genome. What features would you list?arrow_forward
- All the cells of one organism share the same genome. However, during development, some cells develop into skin cells while others develop into muscle cells. Briefly explain how the same genetic instructions can result in two different cell types in the same organism.arrow_forwardA diploid (ie, contains TWO sets of chromosomes) organisms with a 45,000-kb haploid (counts only one set of its chromosomes) genome contains 21% G residues. Calculate the number of A, C, G< and T residues in the DNA of each cell in this organism. Can you help explain why this is the answer, thank you! Answer: Since the haploid genome contains 21% G, it must contain 21% C (Because G=C) and 58% A + T, or 29% A and 29% T. Each cell is a diploid, containing 90,000 kb or 9x10^7 bases. Therefore, A=T = (0.29)(9x10^7) = 2.61 x 10^7 bases and G=C=(0.21)(9x10^7) = 1.89x10^7 bases.arrow_forwardA hereditary disease is inherited as an autosomal recessive trait. The wild-type allele of the disease gene produces a mature mRNA that is 1250 nucleotides (nt) long. Molecular analysis shows that the mature mRNA consists of four exons that measure 400 nt (exon 1), 320 nt (exon 2), 230 nt (exon 3), and 300 nt (exon 4). A mother and father with two healthy children and two children with the disease have northern blot analysis performed. The results of the northern blot for each family member are shown below. a) Identify the genotype of each family member, using the size of mRNAs to indicate each allele. (For example, a person who is homozygous wild type is 1250/1250). b) Based on your analysis, what is the most likely molecular abnormality causing the disease allele?arrow_forward
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