Microbiology: A Systems Approach
5th Edition
ISBN: 9781259706615
Author: Marjorie Kelly Cowan Professor
Publisher: McGraw-Hill Education
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Chapter 18, Problem 9MCQ
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8. Aerobic respiration of a 5 mM solution of tripeptide that is composed of the following three amino acids;
alanine, leucine and isoleucine. Alanine breaks down to pyruvate, leucine breaks down to Acetyl-CoA and
isoleucine breaks down to succinyl-CoA.
Alanine
NADH
FADH2
OP ATP
SLP ATP
Total ATP
Leucine
Isoleucine
Totals
Show your work using dimensional analysis here:
4
9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two
fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure
below. Use the information below to determine how much ATP will be produced from the glycerol part of
the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally
put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your
total number of ATP produced per lipid. Assume no other carbon source is available.
fatty acids
glycerol
18 carbons
12 carbons
0=
influences of environment on the phenotype.
Chapter 18 Solutions
Microbiology: A Systems Approach
Ch. 18.1 - Describe the important anatomical features of the...Ch. 18.1 - Prob. 2AYPCh. 18.2 - Prob. 3AYPCh. 18.3 - Prob. 4AYPCh. 18.3 - Prob. 5AYPCh. 18.3 - Prob. 6AYPCh. 18.3 - Prob. 7AYPCh. 18.3 - Prob. 8AYPCh. 18.3 - Prob. 9AYPCh. 18.4 - Prob. 10AYP
Ch. 18.4 - Prob. 11AYPCh. 18.5 - List the types of normal biota presently known to...Ch. 18.6 - Prob. 13AYPCh. 18.6 - Prob. 14AYPCh. 18 - Prob. 1MCQCh. 18 - Prob. 2MCQCh. 18 - Which of the following is probably the most...Ch. 18 - Prob. 4MCQCh. 18 - Prob. 5MCQCh. 18 - Prob. 6MCQCh. 18 - Prob. 7MCQCh. 18 - Prob. 8MCQCh. 18 - Prob. 9MCQCh. 18 - Prob. 10MCQCh. 18 - Prob. 11TFCh. 18 - Prob. 12TFCh. 18 - Prob. 13TFCh. 18 - Prob. 14TFCh. 18 - Prob. 15TFCh. 18 - Prob. 1CTQCh. 18 - Prob. 2CTQCh. 18 - a. Conduct additional research, and discuss...Ch. 18 - Prob. 4CTQCh. 18 - Prob. 5CTQCh. 18 - Prob. 1VCCh. 18 - Prob. 1CM
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- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
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