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Concept explainers
(a)
Interpretation:
Product formed when ortho-bromonitrobenzene reacts with sodium hydroxide at high temperature has to be drawn.
Concept Introduction:
Nucleophilic
Leaving group: It is a fragment that leaves substrate with a pair of electrons via heterolytic bond cleavage.
Nucleophile donates pair of electrons to positively charged substrate resulting in the formation of
(b)
Interpretation:
Intermediate formed during the reaction between ortho-bromonitrobenzene and sodium hydroxide at high temperature has to be identified.
Concept Introduction:
Nucleophilic aromatic substitution reaction:
Leaving group: It is a fragment that leaves substrate with a pair of electrons via heterolytic bond cleavage.
Nucleophile donates pair of electrons to positively charged substrate resulting in the formation of chemical bond.
(c)
Interpretation:
Reaction that would takes place if the starting material is meta-bromonitrobenzene has to be given.
Concept Introduction:
Nucleophilic aromatic substitution reaction:
Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.
Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho–para directing.
(d)
Interpretation:
Reaction that would takes place if the starting material is para-bromonitrobenzene has to be given.
Concept Introduction:
Nucleophilic aromatic substitution reaction:
Deactivators are electron withdrawing groups attached to the benzenes that have either positive charge or an atom with high electronegativity. They are meta directors.
Activators are electron donating groups attached to the benzenes that have either electron density that is able to push into benzene ring or a lone pair of electrons. They are ortho–para directing.
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Chapter 18 Solutions
Organic Chemistry, Third Edition Binder Ready Version
- A chemistry graduate student is studying the rate of this reaction: 2 HI (g) →H2(g) +12(g) She fills a reaction vessel with HI and measures its concentration as the reaction proceeds: time (minutes) [IH] 0 0.800M 1.0 0.301 M 2.0 0.185 M 3.0 0.134M 4.0 0.105 M Use this data to answer the following questions. Write the rate law for this reaction. rate = 0 Calculate the value of the rate constant k. k = Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol.arrow_forwardNonearrow_forwardNonearrow_forward
- Q2: Label the following molecules as chiral or achiral, and label each stereocenter as R or S. CI CH3 CH3 NH2 C CH3 CH3 Br CH3 X &p Bra 'CH 3 "CH3 X Br CH3 Me - N OMe O DuckDuckarrow_forward1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forward
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