ORGANIC CHEMISTRY (LL)-W/WILEYPLUS
4th Edition
ISBN: 9781119659556
Author: Klein
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 18, Problem 53PP
(a)
Interpretation Introduction
Interpretation:
- The given following compounds synthesized from Benzene have to be explained. Concept Introduction:
- Electrophiles are electron deficient species. In Electrophilic substitution reaction a group or atom in a compound is replaced by electrophile. This kind of reaction occurs predominantly in
aromatic compounds . Electrophilic substitution reactions of aromatic compounds are known as aromatic electrophilic substitution reactions.
- Benzene is an electron rich Aromatic compound. It undergoes aromatic electrophilic substitution reaction.
- The delocalized nature of pi electrons in benzene attributes a special property to benzene called resonance.
- If the substituents on benzene Carbon are Electron rich groups they are known as activating groups. They are ortho- and para- directing groups because these groups when directly bonded to benzene Carbon increases the electron density at ortho and para positions. So they direct the incoming electrophile towards ortho and para position in electrophilic substitution reactions.
- If the substituents on benzene Carbon are Electron withdrawing groups they are known as deactivating groups. They are meta-directing groups because these groups when directly bonded to benzene Carbon decreases the electron density at ortho and para positions and so the incoming electrophile is directed towards meta position.
- Friedel-Crafts Alkylation: This Lewis acid-catalyzed electrophilic aromatic replacement allows the synthesis of alkylated products by means of the reaction of arenes through
alkyl halides oralkenes. - Friedel-Crafts Acylation: This electrophilic aromatic substitution allows the synthesis of monoacylated yield from the reaction stuck between arenes and acyl chlorides or anhydrides. The products are deactivated, as well as do not undergo a second substitution.
(b)
Interpretation Introduction
Interpretation:
- The given following compounds synthesized from Benzene have to be explained. Concept Introduction:
- Electrophiles are electron deficient species. In Electrophilic substitution reaction a group or atom in a compound is replaced by electrophile. This kind of reaction occurs predominantly in aromatic compounds. Electrophilic substitution reactions of aromatic compounds are known as aromatic electrophilic substitution reactions.
- Benzene is an electron rich Aromatic compound. It undergoes aromatic electrophilic substitution reaction.
- The delocalized nature of pi electrons in benzene attributes a special property to benzene called resonance.
- If the substituents on benzene Carbon are Electron rich groups they are known as activating groups. They are ortho- and para- directing groups because these groups when directly bonded to benzene Carbon increases the electron density at ortho and para positions. So they direct the incoming electrophile towards ortho and para position in electrophilic substitution reactions.
- If the substituents on benzene Carbon are Electron withdrawing groups they are known as deactivating groups. They are meta-directing groups because these groups when directly bonded to benzene Carbon decreases the electron density at ortho and para positions and so the incoming electrophile is directed towards meta position.
- Friedel-Crafts Alkylation: This Lewis acid-catalyzed electrophilic aromatic replacement allows the synthesis of alkylated products by means of the reaction of arenes through alkyl halides or alkenes.
- Friedel-Crafts Acylation: This electrophilic aromatic substitution allows the synthesis of monoacylated yield from the reaction stuck between arenes and acyl chlorides or anhydrides. The products are deactivated, as well as do not undergo a second substitution.
(c)
Interpretation Introduction
Interpretation:
- The given following compounds synthesized from Benzene have to be explained. Concept Introduction:
- Electrophiles are electron deficient species. In Electrophilic substitution reaction a group or atom in a compound is replaced by electrophile. This kind of reaction occurs predominantly in aromatic compounds. Electrophilic substitution reactions of aromatic compounds are known as aromatic electrophilic substitution reactions.
- Benzene is an electron rich Aromatic compound. It undergoes aromatic electrophilic substitution reaction.
- The delocalized nature of pi electrons in benzene attributes a special property to benzene called resonance.
- If the substituents on benzene Carbon are Electron rich groups they are known as activating groups. They are ortho- and para- directing groups because these groups when directly bonded to benzene Carbon increases the electron density at ortho and para positions. So they direct the incoming electrophile towards ortho and para position in electrophilic substitution reactions.
- If the substituents on benzene Carbon are Electron withdrawing groups they are known as deactivating groups. They are meta-directing groups because these groups when directly bonded to benzene Carbon decreases the electron density at ortho and para positions and so the incoming electrophile is directed towards meta position.
- Friedel-Crafts Alkylation: This Lewis acid-catalyzed electrophilic aromatic replacement allows the synthesis of alkylated products by means of the reaction of arenes through alkyl halides or alkenes.
- Friedel-Crafts Acylation: This electrophilic aromatic substitution allows the synthesis of monoacylated yield from the reaction stuck between arenes and acyl chlorides or anhydrides. The products are deactivated, as well as do not undergo a second substitution.
Expert Solution & Answer

Trending nowThis is a popular solution!

Students have asked these similar questions
Use the literature Ka value of the acetic acid, and the data below to answer these questions. Note: You will not use the experimental titration graphs to answer the questions that follow.
Group #1:
Buffer pH = 4.35
Group #2:
Buffer pH = 4.70
Group #3:
Buffer pH = 5.00
Group #4:
Buffer pH = 5.30
Use the Henderson-Hasselbalch equation, the buffer pH provided and the literature pKa value of acetic acid to perform the following:
a) calculate the ratios of [acetate]/[acetic acid] for each of the 4 groups buffer solutions above.
b) using the calculated ratios, which group solution will provide the best optimal buffer (Hint: what [acetate]/[acetic acid] ratio value is expected for an optimal buffer?)
c) explain your choice
How would you prepare 1 liter of a 50 mM Phosphate buffer at pH 7.5 beginning with K3PO4 and 1 M HCl or 1 M NaOH? Please help and show calculations. Thank you
Draw the four most importantcontributing structures of the cation intermediate thatforms in the electrophilic chlorination of phenol,(C6H5OH) to form p-chlorophenol. Put a circle aroundthe best one. Can you please each step and also how you would approach a similar problem. Thank you!
Chapter 18 Solutions
ORGANIC CHEMISTRY (LL)-W/WILEYPLUS
Ch. 18.2 - Prob. 1CCCh. 18.3 - Prob. 2CCCh. 18.3 - Prob. 3CCCh. 18.4 - Prob. 4CCCh. 18.5 - Prob. 5CCCh. 18.5 - Prob. 6CCCh. 18.5 - Prob. 7CCCh. 18.6 - Prob. 8CCCh. 18.6 - Prob. 9CCCh. 18.6 - Prob. 10CC
Ch. 18.7 - Prob. 11CCCh. 18.7 - Prob. 12CCCh. 18.8 - Prob. 13CCCh. 18.9 - Prob. 14CCCh. 18.9 - Prob. 15CCCh. 18.10 - Prob. 1LTSCh. 18.10 - Prob. 16PTSCh. 18.10 - Prob. 17ATSCh. 18.11 - Prob. 2LTSCh. 18.11 - Prob. 18PTSCh. 18.12 - Prob. 24CCCh. 18.12 - Prob. 25CCCh. 18.12 - Prob. 5LTSCh. 18.12 - Prob. 26PTSCh. 18.12 - Prob. 6LTSCh. 18.12 - Prob. 28PTSCh. 18.13 - Prob. 30CCCh. 18.13 - Prob. 31CCCh. 18.13 - Prob. 32CCCh. 18.14 - Prob. 33CCCh. 18.14 - Prob. 34CCCh. 18.15 - Prob. 7LTSCh. 18.15 - Prob. 35PTSCh. 18.15 - Prob. 36PTSCh. 18 - Prob. 38PPCh. 18 - Prob. 39PPCh. 18 - Prob. 40PPCh. 18 - Prob. 41PPCh. 18 - Prob. 42PPCh. 18 - Prob. 43PPCh. 18 - Prob. 45PPCh. 18 - Prob. 46PPCh. 18 - Prob. 47PPCh. 18 - Prob. 48PPCh. 18 - Prob. 49PPCh. 18 - Prob. 50PPCh. 18 - Prob. 51PPCh. 18 - Prob. 52PPCh. 18 - Prob. 53PPCh. 18 - Prob. 54PPCh. 18 - Prob. 55PPCh. 18 - Prob. 56PPCh. 18 - Prob. 57PPCh. 18 - Prob. 58PPCh. 18 - Prob. 59PPCh. 18 - Prob. 60PPCh. 18 - Prob. 61PPCh. 18 - Prob. 62PPCh. 18 - Prob. 63PPCh. 18 - Prob. 64PPCh. 18 - Prob. 80IPCh. 18 - Prob. 81IPCh. 18 - Prob. 82IPCh. 18 - Prob. 83IPCh. 18 - Prob. 84IPCh. 18 - Prob. 85IPCh. 18 - Prob. 86IPCh. 18 - Prob. 87IPCh. 18 - Prob. 88IPCh. 18 - Prob. 89IP
Knowledge Booster
Similar questions
- A 100mM lactic acid/lactate buffer was found to have a lactate to lactic acid ratio of 2 and a pH of 4.2. What is the pKa of lactic acid? Can you please help show the calculations?arrow_forwardUsing line angle formulas, draw thestructures of and name four alkanes that have total of 7carbons, one of which is tertiary.Please explain this in detail and can you also explain how to approach a similar problem like this as well?arrow_forwardUsing dashed line wedge projections drawthe indicated compounds and indicate whether thecompound you have drawn is R or S.(a) The two enantiomers of 2-chlorobutane. Can you please explain your steps and how you would approach a similar problem. Thank you!arrow_forward
- 5) There are no lone pairs shown in the structure below. Please add in all lone pairs and then give the hybridization scheme for the compound. (8) 10,11 7) 1.2.3 H 4 | 14 8) COC 12 13 H 16 15 H7 9) - 5.6 C 8 H 10) H 1). 2) 3)_ 11) 12) 13) 4)_ 14) 5) 15) 16) 6)arrow_forwardThe sum of the numbers in the name of isA. 11; B. 13; C. 10; D. 12; E. none of the other answers iscorrect. I believe the awnser should be E to this problem but the solution to this problem is D 12. I'm honestly unsure how that's the solution. If you can please explain the steps to this type of problem and how to approach a problem like this it would be greatly appreciated!arrow_forwardConsider the following data for phosphorus: g atomic mass 30.974 mol electronegativity 2.19 kJ electron affinity 72. mol kJ ionization energy 1011.8 mol kJ heat of fusion 0.64 mol You may find additional useful data in the ALEKS Data tab. Does the following reaction absorb or release energy? 2+ + (1) P (g) + e → P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? 00 release absorb Can't be decided with the data given. yes no ☐ kJ/mol (²) P* (8) + + + e →>> P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): ☐ release absorb Can't be decided with the data given. yes no kJ/mol аarrow_forward
- The number of hydrogens in an alkyne that has a main chain of 14carbons to which are attached a cyclobutyl ring, a benzene ring, an–OH group, and a Br is A. 34; B. 35; C. 36; D. 24; E. 43arrow_forwardHello! I have a 500 Hz H-NMR for 1,5-bis-(4-methoxyphenyl)-penta-1,4-dien-3-one. I need to label the signals with the corresponding H's. Then, find out if the two alkenes are cis or trans by calculating the J values. I believe that I have the H-NMR labeled correctly, but not sure if I got the J values correct to determine if the two alkenes in the compound will make the compound cis or trans.arrow_forwardWhat is the only possible H-Sb-H bond angle in SbH3?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY

Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning

Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning

Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning

Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY