Chapter 1.8, Problem 40P

Use a table to find two consecutive integers between which the solution lies.

$37d+48=368$

To determine

To construct a table to find the two consecutive integers between which the solution lies.

Answer to Problem 40P

8 and 9

Explanation of Solution

Given:

Equation: $37d+48=368$

Calculation:

Consider the given equation,

  $\Rightarrow 37d+48=368$

Create a table for different values of n .

d	$37d+48$	Value of $37d+48$
1	$37(1)+48$	85
2	$37(2)+48$	122
3	$37(3)+48$	159
4	$37(4)+48$	196
5	$37(5)+48$	233
6	$37(6)+48$	270
7	$37(7)+48$	307
8	$37(8)+48$	344
9	$37(9)+48$	381

As the solution to the equation is $37d+48=368$

While observing the table, the values 368 lies between $d=8$ and $d=9$

Conclusion:

Therefore, the values lie between 8 and 9.